Answer:
cos(O) = 39 / 89
Step-by-step explanation:
Given:
ΔOPQ, where
∠Q=90°
PO = 89
OQ = 39
QP = 80
cosine of ∠O?
cos(O) = Adjacent / Hypotenuse
cos(O) = 39 / 89
Answer:
X ≥ 3.5
Step-by-step explanation:
-2x-6≤1
+6 +6
-2x≤7
-2x/2 7/2
x ≥ 3.5
Answer:
2 gigabytes of data
Step-by-step explanation:
Given
Amount Jason keeps per month = $68.90
Cost of flat per month = $60.50
Balance for data = 68.90-60.50
Balance for data = $8.40
If 1Gigabyte = $4
x = $8.40
Cross multiply
4x = 8.40
x = 8.40/2
x = 2.20
Hence Jason can only use 2 gigabytes of data while staying within his budget
Answer:
The height h it will travel in t minutes
Height h = 6 + 20(t)
Oh=20t + 6
Step-by-step explanation:
A hot air balloon starts at a height of 6 feet above the ground and then rises at a rate of 20 feet each minute.
Initial height h0 = 6 feet
Then it travel 29 feet each minute
Rate = 20 feet/ minute
The height h it will travel in t minutes
Height h = 6 + 20(t)
Answer:
Step-by-step explanation:
multiply lengthx weith