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Jet001 [13]
3 years ago
15

Prove a/b is less than b/a when 0 < a <b

Mathematics
1 answer:
enyata [817]3 years ago
7 0

\frac{a}{b} < \frac{b}{a} \implies \\ a^2 < b^2 \implies a-b

We are given that 0<a<b, which means that 0>-a>-b if you multiply it by -1, which means what's given by our inequality is true and we are done.

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\frac{7}{24} ÷ \frac{35}{48}
Multiply \frac{7}{24} by the reciprocal of \frac{35}{48}, which is \frac{48}{35}

=\frac{7}{24} × \frac{48}{35}
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We can simplify it further:
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\frac{336/168}{840/168}

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