Answer:
B. cosθ ≠ 0
Step-by-step explanation:
As we notice, tanθ is a fraction. Fractions are undefined when the denominator is equal to or approaching 0 because one cannot divide by zero. Thus, the denominator in this case is cosθ, and therefore it cannot equal zero for the equation to be true.
Answer:
2587mm^3 approx!
Step-by-step explanation:
first you divide the nut into 6 part(in triangle now, by joining centre to each edge)
let's take one part of the triangular shape then area of that part can be found by using 1/2×base×height
i.e, 1/2×13×15=97.5(mm^2)
now when we consider depth of that traingular part,we will get volume of that part as area×depth
i.e, 97.5×6=585(mm^3)
now volume of all the 6 triangular part is 585×6=3510(in mm^3)
now take circular cavity in consideration, it's volume will be π(7^2)6=923(mm^3) approximately
now reqired volume will be volume of that hexagonal part minus that of circular cavity
=3510-923
=2587mm^3
✌️
If x is fish, y is octopi, and z is crabs, then you would have to know the numbers.
Then your answer would be c. 30x+80y-15z.
Because x=+30, y=+80, and z=-15.
I hope that helps. If you need any further help on this problem just ask.
Answer:
<h3>C. They are both perfect squares and perfect cubes.</h3>
Step-by-step explanation:
Perfect squares are numbers that their square root can be found easily without any remainder.
Given the following patterns;
1*1 = 1 and 1*1*1 = 1
It can be seen that 1 is 1 perfect square since 1*1 = 1² = 1
Also 1 is perfect cube since 1*1*1 = 1³ = 1 (cube of the value gives 1)
Similarly for the expression;
8*8 = 64
8² = 64 (since the square of 8 gives 64, then 64 is known to be a perfect square)
Also 4*4*4 = 64
i.e 4³ = 64 (This shows that the cube root of 64 is 4 making it a perfect cube since we can get a whole number for the cube root of 64)
The same is applicable for other expressions 729 = 27 × 27, and 9 × 9 × 9, 4,096 = 64 × 64, and 16 × 16 × 16
This values are easily expressed as a constant multiple of a number showing that they are both perfect squares and perfect cubes.
