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Svetllana [295]
3 years ago
7

13p - 3 = 5p + 13 find p please

Mathematics
2 answers:
densk [106]3 years ago
7 0
P=2. Hope this helps
marin [14]3 years ago
6 0
First add 3 to both sides of the equation.
13p= 5p + 16

Next subtract 5p from both sides of the equation. 8p = 16

Divide both sides by 8 so you can get p by itself. p = 2

ANSWER : p=2
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YASSSSSSSSSSSSSSSSSSSSSSS
Lunna [17]

Answer:

Nobody cares, this is a forum that has to do with questions for questions regarding school, not unintelligent stuff like this

Step-by-step explanation:

7 0
3 years ago
A teacher gave her class two exams; 60% of the class passed the second exam, but only 48% of the class passed both exams. What p
Levart [38]
The answer is the last one - 48%
3 0
3 years ago
A) The sum of −3x+5 and 7−4x is subtracted from 5x+17.
AlekseyPX
A. -3x+5+7-4x 
  -3x-4x+5+7 
-7x+12 

-7x+12-5x+17 
-7x-5x+12+17
-12x+29

B. -5*(x+2)= -5x-10
-6x-1+ (-5x-10)= -6x-5x-1-10=
  -11x-11

8 0
3 years ago
10m^2 of tiles cover a pool, the pool is shaped as a square, so all four edges are the same, and the depth is constant but not e
nignag [31]
Assume:

Size of sides = x m
Depth of the pool = y m

Therefore, surface area = x^2+4xy =10 m^2

Then, y = (10-x^2)/(4x)

Now,
Volume (V) = x^2*y = x^2*y =x^2(10-x^2)/4x = (10x-x^3)/4 = 1/4(10x-x^3)
For maximum volume, first derivative of volume function is equal to zero.
That is,
dV/dx =0 = 1/4(10-3x^2)
Then,
1/4(10-3x^2) = 0
10-3x^2 = 0
3x^2=10
x= sqrt (10/3) = 1.826 m
And
y= (10-1.826^2)/(4*1.826) = 0.913 m

Therefore,
V= 1.826^2*0.913 = 3.044 m^3
3 0
3 years ago
Answer choice (A)5/30 (B)3/17 (C) 8/30 (D) 16/30
ratelena [41]
<h3>Answer: (C) 8/30</h3>

===================================================

Explanation:

There are 5+3 = 8 people in choir and running club. I added the values in the overlapped region of the circles "choir" and "running club".

This is out of 2+5+6+7+3+4+3 = 30 people total.

Divide the two results to form the fraction 8/30

Ideally we should reduce to get 4/15, but your teacher has chosen not to reduce.

8 0
3 years ago
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