The sum of the angles of a triangle is 180º.
We have three angles:
∠yxz=3x+5
∠xzy=180º-(8x-14)
∠xyz=4x
Therefore:
(3x+5º) + [180º-(8x-14º)]+(4x)=180º
3x-8x+4x=180º-5º-14º-180º
-x=-19º
x=19º
∠yxz=3x+5º =3(19º)+5º=62º
∠xzy=180º-(8x-14)=180º-(8(19º)-14)=42º
∠xyz=4x=4(19º)=76º
Answer: m∠yxz= 62º.
Answer:
eight plus three times a number
Step-by-step explanation:
I think I'm wrong I don't know I'm not really the master at this (but feel free to do tell me if I'm wrong)
The Answer to <span>8x-6>12+2x = x>3</span>
Answer:

Step-by-step explanation:
Given
, start by squaring both sides to work towards isolating
:

Recall
and
:

Isolate the radical:

Square both sides:

Expand using FOIL and
:

Move everything to one side to get a quadratic:

Solving using the quadratic formula:
A quadratic in
has real solutions
. In
, assign values:

Solving yields:

Only
works when plugged in the original equation. Therefore,
is extraneous and the only solution is 