Ask question

Ask question

All categories

goldfiish [28.3K]

3 years ago

6

What is the value of p? 4 × 11 × p = 11 × 4 × 5 PLZ

2 answers:

Morgarella [4.7K]3 years ago

6 0

Using the multiplicative property, we know that a * b * c = c * b * a
So, we can conclude that the answer is 5 because 4 × 11 × 5 = 11 × 4 × 5.

Hope this helps!

madam [21]3 years ago

3 0

4 * 11 * p = 11 * 4 * 5

Divide both sides by 4.

11 * p = 11 * 5

Divide both sides by 11.

p = 5

You might be interested in

Write four decimals with the digit four in a different place in each ones, tenths , hundredths, and thousandths .Then write a st

crimeas [40]

4.1.....the 4 in the ones place is 10 times bigger then the 4 in the tenths place and 100 times bigger then the 4 in the hundredths place and 1000 times bigger then the 4 in the thousandths place

2.4..the 4 in the tenths place is 10 timed bigger then the 4 in the hundredths place and 100 times bigger then the 4 in the thousandths place

3.14...the 4 in the hundredths place is 10 times bigger then the 4 in the thousandths place

5.124...this 4 in the thousandths place is the smallest

8 0

3 years ago

Which is not an equation of the line going through (3,-6) and (1, 2)?

Olegator [25]

Answer:

○ $\displaystyle y - 1 = -4(x - 2)$

Step-by-step explanation:

When you plug these coordinates into this equation, they will be confirmed as <em>false</em>.

I am joyous to assist you anytime.

3 0

3 years ago

What is undefined <br> I need help I don't understand this question

timurjin [86]

(4/9-9) and (4/0) are undefined as you can not divide by the value of 0.

4 0

3 years ago

The length of rectangle is 3 more than twice the width

kykrilka [37]

Answer:

The length of a rectangle is 3” more than twice the width. The area of the rectangle is 150 in^2. Find the dimensions of the rectangle.

The length of a rectangle is 3” more than twice the width. The area of the rectangle is 150 in^2. Find the dimensions of the rectangle.

Wyzant

MATH QUADRATIC FORMULA

Kyle C. asked • 05/05/16

The length of a rectangle is 3” more than twice the width. The area of the rectangle is 150 in^2. Find the dimensions of the rectangle.

The length of a rectangle is 3” more than twice the width. The area of the rectangle is 150 in^2. Find the dimensions of the rectangle.

ANSWER

ABOUT THIS TUTOR ›

We know that Area = Length x Width

in this case, L = 2W + 3 and A = 150in2

so, 150in2 = W x (2w + 3)

150in2 = 2W2 + 3W

rearranging, 2W2 + 3W - 150in2 = 0

we need to use the quadratic formula to solve this equation

that formula is [-b±(√b2 -4ac)]/2a

a = 2, b = 3, c = -150

inserting those values, we get [-3±(√32 -4•2•-150)]/2•2

which becomes (-3±√1209)/4

we get (-3 ± 34.771)/4

we can discard the negative value, because no length can be negative

so, W ≅ 7.942 inches

then L = 2W + 3 ≅ 18.886 inches

Proof: 7.942in x 18.886in ≅ 149.99

HOPE IT'S HELPFUL

THANK YOU

4 0

3 years ago

A tennis ball is 2 inch in diameter. How many tennis ball will fill a room of 20ft by 16ft by 18ft if no space wasted?

krek1111 [17]

The number of tennis ball that will fill the room is <u>1,371 tennis balls.</u>

<em><u>Given</u></em>:

Diameter of ball (d) : 2 inch

Radius (r) = half of diameter = 1 inch

Dimension of room = 20ft by 16ft by 18ft

Number of balls that will fill the room = Volume of each ball/volume of the room

Volume of the ball = volume of a sphere = $\frac{4}{3} \pi r^{3}$

Where,

r = 1

let $\pi = 3.14$

<em>Substitute</em>:

$Volume = \frac{4}{3} \times 3.14 \times 1^{3} \\Volume = 4.2in^{3}$

Volume of the room = $20 \times 16 \times 18 \\$

$= 5,760$

Therefore:

number of tennis balls that will fill the room = $\frac{5,760}{4.2} = 1,371.4$

Therefore, the number of tennis ball that will fil the room will be <u>approximately 1,371.</u>

Learn more about volume here:

brainly.com/question/16098833

7 0

2 years ago