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Advocard [28]
3 years ago
15

On a clear day you can see about 25.2 miles from the upper observation platform of the Eiffel tower in Paris. Using the formula

below, estimate the height in feet, h, of the upper observation platform.
d=\frac{5}{6} \sqrt{h}

A. 875 feet
B. 4.2 miles
C. 529 feet
D. 914 feet
Mathematics
2 answers:
fredd [130]3 years ago
8 0

Answer:

D. 914 feet

Step-by-step explanation:

We are given the distance that a person can see on a clear day from the upper observation platform of the Eiffel tower in Paris. We are then required to estimate the height of the upper observation platform using the formula;

d=\frac{5}{6}\sqrt{h}

Where d is the distance and h the height of the upper observation platform. The first step would be to solve for h, that is make h the subject of the formula in the above equation;

We multiply both sides of the equation by the reciprocal of 5/6 which is 6/5;

\sqrt{h}=\frac{6}{5}d

The next step is to eliminate the square root on the Left Hand Side of the equation by squaring both sides;

h=1.44d^{2}

Given d is 25.2, h becomes;

h=1.44*25.2^{2}\\h=914.4576

To the nearest whole number, h becomes 914

Crank3 years ago
3 0

Answer: 914 ft

Step-by-step explanation:

a p e x

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What is the value of x if x over 5=3
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2 years ago
Read 2 more answers
Expand the following expression:<br> (2x-1)(x+4)
sesenic [268]

Answer:

2x² +7x - 4

Step-by-step explanation:

(2x-1)(x+4)

2x² + 8x - x - 4

simplify:

2x² +7x - 4

8 0
3 years ago
00:00
Furkat [3]

Answer:

-2

Step-by-step explanation:

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5 0
4 years ago
Noah has a summer tree-trimming business. Based on experience, Noah knows that his profit, P, in dollars, can be modelled by = −
crimeas [40]

Solving quadratic equations, it is found that he needs to charge:

1. He needs to charge $40 to break even.

2. He needs to charge $30 for a profit of $600.

<h3>What is a quadratic function?</h3>

A quadratic function is given according to the following rule:

y = ax^2 + bx + c

The solutions are:

  • x_1 = \frac{-b + \sqrt{\Delta}}{2a}
  • x_2 = \frac{-b - \sqrt{\Delta}}{2a}

In which:

\Delta = b^2 - 4ac

The profit equation in this problem is:

P(x) = -3x² + 150x - 1200.

He breaks even when P(x) = 0, hence:

-3x² + 150x - 1200 = 0.

The coefficients are a = -3, b = 150, c = -1200, hence:

  • \Delta = 150^2 - 4(-3)(-1200) = 8100
  • x_1 = \frac{-150 + \sqrt{8100}}{-6}
  • x_2 = \frac{-150 - \sqrt{8100}}{-6} = 40

He needs to charge $40 to break even.

For a profit of $600, we have that P(x) = 600, hence:

-3x² + 150x - 1200 = 600.

-3x² + 150x - 1800 = 0.

The coefficients are a = -3, b = 150, c = -1800, hence:

  • \Delta = 150^2 - 4(-3)(-1800) = 900
  • x_1 = \frac{-150 + \sqrt{900}}{-6}
  • x_2 = \frac{-150 - \sqrt{900}}{-6} = 30

He needs to charge $30 for a profit of $600.

More can be learned about quadratic equations at brainly.com/question/24737967

#SPJ1

6 0
2 years ago
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