Answer:
We accept the null hypothesis and reject the alternate hypothesis. There is no evidence to conclude that the population mean is greater than 29. The population mean is less than or equal to 29.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 29
Sample mean, 
= 30
Sample size, n = 47
Alpha, α = 0.05
Population standard deviation, σ = 5
First, we design the null and the alternate hypothesis
a) This is a one-tailed test because the alternate hypothesis is in greater than direction.
We use One-tailed z test to perform this hypothesis.
b) 
, we reject the null hypothesis and accept the alternate hypothesis and if 
, we accept the null hypothesis and reject the alternate hypothesis.
c) Formula:
Putting all the values, we have
d) Now, 
Since,
We accept the null hypothesis and reject the alternate hypothesis. There is no evidence to conclude that the population mean is greater than 29. The population mean is less than or equal to 29.
e) P-value is 0.0853
On the basis of p value we again accept the null hypothesis.
Answer:
x -4 -3 -2 -1 0 1 2 3 4
y -54 -20 -4 0 -2 -4 0 16 50
at 4 it is maximum .
maximum value=50
hope that helps
Slope intercept form is y = mx + b
Pick one of the coordinates, I’ll use (-3,-4) as the example.
Coordinates are just numbers plugged in for (x,y).
This means -3 would be your x and -4 would be your y.
So plug these numbers into the equation and you get -4 = m(-3) + b.
M is slope and to find slope, you need to do (y2-y1) / (x2-x1).
In other words, it would be (-3 - -4) / (4 - -3) = 1/7 which is your slope (m).
Now plug that in for m to get the b variable.
-4 = 1/7(-3) + b.
B = -3.57
Your answer is y = 1/7x -3.57
Answer:
See below
Step-by-step explanation:
a = 15 sqrt 2 sin 45
= 15 sqrt 2 * sqrt( 2 ) /2 = 15 * 2 /2 = 15
sin 60 = a/c
sqrt(3)/2 = 15/c
c = 15 / ( sqrt(3)/2) = 30 / sqrt 3 = 30 sqrt 3 /3 = 10 sqrt 3
