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zhannawk [14.2K]
3 years ago
12

15=-5x+10 plz solve will mark brainlest

Mathematics
2 answers:
brilliants [131]3 years ago
6 0

Answer: X= -1

Step-by-step explanation:

Subtract 10 from both sides.

then Divide both sides by -5.

Gnoma [55]3 years ago
4 0
Step by step Explanation:
First, you need to subtract 10 from each side leaving 5 on the left and -5x on the right. Then, you will need to divide each side by -5 inorder to receive -1=x as your answer.
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At what value of x do the graphs of the equations below intersect <br> 2x-y=6 <br> 5x+10y=-10
Irina18 [472]

Answer:

The graphs of the equations intersect at x=2

Step-by-step explanation:

we have

2x-y=6 ----> equation A

5x+10y=-10 ----> equation B

Solve the system by graphing

Remember that the solution of the system of equations is the intersection point both lines

Using a graphing tool

The solution is the point (2,-2)

see the attached figure

therefore

The graphs of the equations intersect at x=2

5 0
3 years ago
1 cubic foot of sand weighs 100 lb. a square sandbox with 5 foot sides has a half of a foot of sand in it. how many pounds of sa
klasskru [66]
1250. Cubic feet = volume and volume is length * width * height. The volume of this would be 5x5x(1/2), which equals 12.5 cubic feet. 12.5*100=1250
5 0
3 years ago
How do I solve for x?
NISA [10]
Write and solve an equation of ratios based upon the fact that the small and large triangles shown are similar:

 5          6
---- = ---------
14      6 + x

Then 30 + 5x = 84, and 5x = 54, and so x = 54/5, or 10.8, or 10 4/5.
5 0
3 years ago
( 5 + 0) +4=5 +4 what property of addition is this
sergeinik [125]

Answer:

Associative Property

Step-by-step explanation:

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4 0
3 years ago
How do you find the quadratic function with vertex (-2,5) and point (0,9)?
Anastaziya [24]

Answer: y = (x +2)² + 5

<u>Step-by-step explanation:</u>

y = a(x - h)² + k <em>where "a" is the leading coefficient and (h, k) is the vertex</em>

Since we don't know "a", we need to plug in the point (x, y) and the vertex (h, k) to solve for "a":  (x, y) = (0, 9) and (h, k) = (-2, 5)

y = a(x - h)² + k

9 = a(0 - (-2))² + 5

9 = a(0 + 2)² + 5

9 = a(2)² + 5

<u>-5 </u>   <u>          -5 </u>

4  =  a(4)

<u>÷4 </u>   <u> ÷4   </u>

 1 = a

Next, plug in "a" and the vertex (h, k):

y = a(x - h)² + k

y = 1(x +2)² + 5

y = (x +2)² + 5


6 0
4 years ago
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