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olya-2409 [2.1K]
3 years ago
11

How do you find the quadratic function with vertex (-2,5) and point (0,9)?

Mathematics
1 answer:
Anastaziya [24]3 years ago
6 0

Answer: y = (x +2)² + 5

<u>Step-by-step explanation:</u>

y = a(x - h)² + k <em>where "a" is the leading coefficient and (h, k) is the vertex</em>

Since we don't know "a", we need to plug in the point (x, y) and the vertex (h, k) to solve for "a":  (x, y) = (0, 9) and (h, k) = (-2, 5)

y = a(x - h)² + k

9 = a(0 - (-2))² + 5

9 = a(0 + 2)² + 5

9 = a(2)² + 5

<u>-5 </u>   <u>          -5 </u>

4  =  a(4)

<u>÷4 </u>   <u> ÷4   </u>

 1 = a

Next, plug in "a" and the vertex (h, k):

y = a(x - h)² + k

y = 1(x +2)² + 5

y = (x +2)² + 5


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Answer:

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ctto JBarnum

Step-by-step explanation:

P+11=(1/2)(P-13)^2

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2P+22=P^2-26p+169

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checking:

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