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olya-2409 [2.1K]
3 years ago
11

How do you find the quadratic function with vertex (-2,5) and point (0,9)?

Mathematics
1 answer:
Anastaziya [24]3 years ago
6 0

Answer: y = (x +2)² + 5

<u>Step-by-step explanation:</u>

y = a(x - h)² + k <em>where "a" is the leading coefficient and (h, k) is the vertex</em>

Since we don't know "a", we need to plug in the point (x, y) and the vertex (h, k) to solve for "a":  (x, y) = (0, 9) and (h, k) = (-2, 5)

y = a(x - h)² + k

9 = a(0 - (-2))² + 5

9 = a(0 + 2)² + 5

9 = a(2)² + 5

<u>-5 </u>   <u>          -5 </u>

4  =  a(4)

<u>÷4 </u>   <u> ÷4   </u>

 1 = a

Next, plug in "a" and the vertex (h, k):

y = a(x - h)² + k

y = 1(x +2)² + 5

y = (x +2)² + 5


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Marty and Ethan both wrote a function, but in different ways.
marishachu [46]

<em><u>Question:</u></em>

Marty and Ethan both wrote a function, but in different ways.

Marty

y+3=1/3(x+9)

Ethan

x y

-4 9.2

-2 9.6

0 10

2 10.4

Whose function has the larger slope?

1. Marty’s with a slope of 2/3

2. Ethan’s with a slope of 2/5

3. Marty’s with a slope of 1/3

4. Ethan’s with a slope of 1/5

<em><u>Answer:</u></em>

Marty’s with a slope of 1/3 has the larger slope

<em><u>Solution:</u></em>

<em><u>Given that Marty equation is:</u></em>

y + 3 = \frac{1}{3}(x+9)

<em><u>The point slope form is given as:</u></em>

y - y_1 = m(x-x_1)

Where, "m" is the slope of line

On comapring both equations,

m = \frac{1}{3}

<em><u>Ethan wrote a function:</u></em>

Consider any two values from the table we have;

(0, 10) and (2, 10.4)

<em><u>The slope is given by formula:</u></em>

m = \frac{y_2-y_1}{x_2-x_1}

From above two points,

(x_1, y_1) = (0, 10)\\\\(x_2, y_2) = (2, 10.4)

Therefore,

m = \frac{10.4-10}{2-0}\\\\m = \frac{0.4}{2} \\\\m = 0.2

Thus we get,

\text{Slope of Ethan} < \text{Slope of Marty}

Therefore, Marty’s with a slope of 1/3  has the larger slope

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