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artcher [175]
3 years ago
7

Find the area of the parallelogram with the following vertices:

Mathematics
1 answer:
igomit [66]3 years ago
6 0

Answer:

-12.5

Step-by-step explanation:

To easily get the area of the parallelogram, we will label the vertices .

A= 1, -2.... X1, y1

B= 5,8... X2, y2

C= 3,3.... X3, y3

D= 0,8.... X4, y4

Before that, let me state that:

The Area of a parallelogram is defined as :

1/2 det (X1 (y2 - y3) + X2 ( y3 - y1) + X3 (y1 - y2)

In the order from the question:

A = (-2(8-3) + 5(3-3) + 3( 3-8)) / 2

A = -2(5) + 5(0) + 3(-5)

A = -10 + 0 - 15 / 2

A = -25/2

A = -12.5

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Which of these is NOT an integer
Tema [17]

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

Option A

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

\boxed{\text{Option A:}}\\\\3^{-5}\\\\\rightarrow \frac{1}{3^5}\\\\\rightarrow  \frac{1}{243}\\\\\ \text{This is \textbf{NOT} an integer.}}

⸻⸻⸻⸻

\boxed{\text{Option B:}}\\\\-3^5\\\\\rightarrow -3 * -3 * -3 * -3 * -3 \\\\\rightarrow \boxed{-243}\\\\\\\text{This \textbf{IS} an integer.}

⸻⸻⸻⸻

\boxed{\text{Option C:}}\\\\\frac{1}{3}^{-5} \\\\\rightarrow \frac{1}{(\frac{1}{3})^5}\\\\\rightarrow \frac{1}{\frac{1}{243} }\\\\\rightarrow \boxed{243}\\\\\\\text{This \textbf{IS} an integer.}

⸻⸻⸻⸻

\text{Option \textbf{A} does not simplify into an integer.}

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

7 0
3 years ago
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Lapatulllka [165]

Answer:

The last option

Step-by-step explanation:

she did not change the sign of +6 to -6

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Answer:

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