1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Naddika [18.5K]
3 years ago
6

Which system of equations can you

Mathematics
1 answer:
Yuki888 [10]3 years ago
3 0
The answer is <span>y = 2x3 + 4x2 – x + 5 and  y = –3x2 + 4x + 9
Roots are both: x=-4, x= -1/2 , x= 1

Proof:

Solve for x over the real numbers:
2 x^3 + 4 x^2 - x + 5 = -3 x^2 + 4 x + 9

Subtract -3 x^2 + 4 x + 9 from both sides:
2 x^3 + 7 x^2 - 5 x - 4 = 0

The left hand side factors into a product with three terms:
(x - 1) (x + 4) (2 x + 1) = 0

Split into three equations:
x - 1 = 0 or x + 4 = 0 or 2 x + 1 = 0

Add 1 to both sides:
x = 1 or x + 4 = 0 or 2 x + 1 = 0

Subtract 4 from both sides:
x = 1 or x = -4 or 2 x + 1 = 0

Subtract 1 from both sides:
x = 1 or x = -4 or 2 x = -1

Divide both sides by 2:

Answer:  x = 1 or x = -4 or x = -1/2
</span>
You might be interested in
Decimals to fractions 3/4=?
GrogVix [38]
.75 is the decimal form of 3/4
7 0
3 years ago
Three numbers have a mean of 64. When a fourth number is included the mean is doubled. What is the fourth number?
astra-53 [7]
The mean is calculated by adding up all of the given numbers and dividing by the number of numbers.

Lets, for ease of understanding, say that the first three number were 64...

Mean=(64+64+64)/3=192/3=64

Now, lets solve for the mean where 'x' is the unknown fourth number and 128 is the mean. (since, the answer said that when the fourth number was added the mean, 64, was doubled '64*2=128')

128=(64+64+64+x)/4
128=(192+x)/4
Multiply both sides by 4
512=192+x
subtract 192 from both sides
320=x

The missing number is 320..


Now lets double check our work.

Mean=(64+64+64+320)/4=512/4=128

Answer=320
8 0
3 years ago
Read 2 more answers
A card is drawn from a pack of 52 cards. Find the probability of drawing an ace given that it is diamond.4/521/132/134/13
ICE Princess25 [194]

Solution:

The probability of an event is expressed as

P(event)=\frac{number\text{ of desired outcome}}{number\text{ of possible outcome}}

In a pack of 52 cards, we have

\begin{gathered} number\text{ of diamonds=13} \\ number\text{ of ace= 1} \end{gathered}

Thus, we have the probability to be evaluated as

P(ace)=\frac{1}{13}

8 0
1 year ago
BRAINLIEST TO CORRECT
Fynjy0 [20]
Make the fractions improper:
33/4 + 14/5

Find common denominator:
165/20 + 56/20

Add:
221/20

Answer:
11 1/20
7 0
3 years ago
Read 2 more answers
Need some answers for this one
Schach [20]

Answer:

20.6

Step-by-step explanation:

Since the diameter of each circle is 4, the dimensions of the rectangle is 8x12

The area of the whole rectangle is 96

Now we need to find the area of the circles

The area of 1 circle is 2^{2} *\pi =12.56...

So the area of all 6 circles is 12.56*6= 75.39...

So to find the area of yellow you have to subract the area of circle from the overall area of the rectangle

96-75.4=20.6

4 0
3 years ago
Other questions:
  • Please help! i'm not good with algebra nor chemistry.
    14·1 answer
  • Mark purchased a Playstation on sale at a 40%
    6·1 answer
  • 3 trips in 14 months
    14·2 answers
  • I need these three solved. I have a lot of math to do. the directions say solve each system of equations using substitution. sho
    5·1 answer
  • Complete this statement 40xa^2+24ax+32a=8a( )
    10·1 answer
  • Three dogs eat 30 pounds of food in 10 days. If each dog eats the same amount, how much food does 1 dog eat in 1 day? 1 pound 3
    15·2 answers
  • Which body system is responsible for exchange of oxygen and carbon dioxide between the body and the atmosphere?
    8·2 answers
  • Anyone need advice on how to come out? Answer if so. LGBTQ+ peeps only answer.
    7·2 answers
  • Find x please help me
    13·2 answers
  • Please Help Fast This Is Important.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!