the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x. Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set. if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times. This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
Answer:
Data is quantitative, data is categorical, data must be from a simple random sample, the data mut have normal distribution,
Step-by-step explanation:
When we make inference about one population proportion, we must ensure that the sample was taken randomly and observations follow a normal distribution. The sample size must be as large as possible with at least 10 counts of failures an 10 counts of successes. The individual observations must be independent. They must be quantified and categorized.
Step-by-step explanation:
$31.50 is how much she made
418.5 is how much the store made, but, that is the simple value, there could be more variables
70-3·6+9
Remember PEMDAS.
You must multiply the 3 and 6 together, and you would get 18.
Then, you subtract 18 from 70, which would give you 52.
And finally, you would add 9 to 52, getting 61 as your final answer.
