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Viktor [21]
4 years ago
5

NEED HELP FAST!

Mathematics
1 answer:
motikmotik4 years ago
7 0
Add the equations to eliminate x.
Because the first equation has x and the second has -x, added together, they cancel each other out. When you add the rest of the equation, you get 2y=22. You can then divide by 2 to get y=11.
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How would you do this last part?
alina1380 [7]

Answer:

broken heart thats the last one lol

Step-by-step explanation:

8 0
3 years ago
Do I set the equation up like this and then multiply the 2 on everything?
dybincka [34]
No no need to  take out the 2 
You can factor this by using the ac method

2x^2 + 3x - 5 = 0

multiplying the first and last coefficients 2 * -5 = -10
Now we want to get 2 factors of -10  which will give us  +3 when added:-
+5 and -2  seem ok so we write:-

2x^2 - 2x + 5x - 5 = 0

2x(x - 1) + 5 (x - 1) =0

(2x + 5)(x - 1) = 0

Solution is   x = -5/2  and x = 1
3 0
4 years ago
A twelve-sided die with sides labeled through will be rolled once. Each number is equally likely to be rolled. What is the proba
FromTheMoon [43]

<em>Complete Question:</em>

<em>A twelve-sided die with sides labeled 1 through 12 will be rolled once. Each number is equally likely to be rolled, what is the probability of rolling a number greater than 10?</em>

Answer:

P(T) = \frac{1}{6}

Step-by-step explanation:

Given

Number of Sides = 12

Required

Probability of obtaining a side greater than 10

We start by listing out the sample space;

S = \{1,2,3,4,5,6,7,8,9,10,11,12\}

n(S) = 12

Next, we list out digits greater than 10; Represent this with T

T = \{11,12\}

n(T) = 2

Probability of T is calculated as follows;

P(T) = \frac{n(T)}{n(S)}

P(T) = \frac{2}{12}

Divide the numerator and denominator by 2

P(T) = \frac{1}{6}

<em>Hence, the required probability is </em>\frac{1}{6}<em />

8 0
3 years ago
Find a, b∈|R, knowing that the systems {3x+4y=10 and {bx+ay=7
xenn [34]
X=2, y=1, a=1, b=3.
6 0
3 years ago
Read 2 more answers
a gardener has 8 pounds of fertilizer. He packs the fertilizer into 5/8 pound bags. What is the maximum number of 5/8 pound bags
navik [9.2K]
A gardener has 8 pounds of fertilizer. He packs the fertilizer into 5/8 pound bags. What is the maximum number of 5/8 pound bags he can pack?

so first you multiply 8 pounds times 5 from 5/8 which is 40/8 pounds bags
now how many 8s can fit in 40 
40 divided by 8 =5 
so he can pack 5 maximum bags
7 0
3 years ago
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