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3 years ago

How can I determine the line of best fit, and how will this help me to make predictions?

Mathematics

2 answers:

HACTEHA [7]3 years ago

4 0

Answer:

A line of best fit can be roughly determined using an eyeball method by drawing a straight line on a scatter plot so that the number of points above the line and below the line is about equal (and the line passes through as many points as possible).

uysha [10]3 years ago

4 0

Answer: Draw a straight line on a scatter plot.

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Barry is 8 years older than his sister. In 3 years, he will be twice as old as she will be then. How old is each now?

Colt1911 [192]

Answer:

Step-by-step explanation:

Present age of Barry = b

Present age of sister = s

Barry is 8 years older than his sister means if we subtract 8 from present age of Barry both will be of equal age

s=b-8 ............(1)

In 3 years means we have to add 3 in their present age

s+3=b+3

then

he will be twice as old as

2(s+3)=(b+3

2s+6=b+3

2s=b+3-6

2s=b-3...............(2)

Put the value of s from (1) to (2), we have

2(b-8)=b-3

2b-16=b-3

2b-b=-3+16

b=13

Put the value of b in (1)

s=13-8

s=5

Present age of Barry = b = 13

Present age of sister = s = 5

7 0

3 years ago

GARDEN Amanda is planting flowers in a rectangular garden. She wants to know the amount of space in her backyard the garden will

Andrew [12]

The function A(x) = 2x²-3x-2 represents the area of the garden.

Step-by-step explanation:

Given,

Length of rectangular garden is given by;

L(x) = 2x+1

Width of rectangular garden is given by;

W(x) = x-2

Area of rectangular garden;

A(x) = L(x) * W(x)

$A(x) = (2x+1)(x-2)\\A(x) = 2x(x-2)+1(x-2)\\A(x) =2x^2-4x+x-2\\A(x) = 2x^2-3x-2$

The function A(x) = 2x²-3x-2 represents the area of the garden.

Keywords: Area, rectangle

Learn more about area at:

#LearnwithBrainly

6 0

3 years ago

Show work. This is a BC calculus problem.

stepan [7]

Answer:

Step-by-step explanation:

Remember that the limit definition of a derivative at a point is:

$\displaystyle{\frac{d}{dx}[f(a)]= \lim_{x \to a}\frac{f(x)-f(a)}{x-a}}$

Hence, if we let f(x) be ln(x+1) and a be 1, this will yield:

$\displaystyle{\frac{d}{dx}[f(1)]= \lim_{x \to 1}\frac{\ln(x+1)-\ln(2)}{x-1}}$

Hence, the limit is equivalent to the derivative of f(x) at x=1, or f’(1).

The answer will thus be D.

5 0

3 years ago

suppose y varies directly with x and y=5 when x=20. Write a direct variation equation then find the value of x when y=3/2

jek_recluse [69]

X=k*Y
K*Y=X
K=X/Y
K=20/5
K=4

For Y=3/2
X=k*3/2
X=4*3/2
X=6

6 0

4 years ago

Eddi Din [679]

Answer: The relative frequency of column A in group 1= $0.75$

The relative frequency of column B in group 1= $0.25$

The relative frequency of column A in group 2= $0.56$

The relative frequency of column B in group 2= $0.44$

Step-by-step explanation:

The relative frequency is the ration of each frequency by the total value in particular group.

For group 1 : Total =102+34=136

The relative frequency of column A in group 1= $\frac{102}{136}=0.75$

The relative frequency of column B in group 1= $\frac{34}{136}=0.25$

For group 2 : Total =18+14=32

The relative frequency of column A in group 2= $\frac{18}{32}=0.5625\approx0.56$

The relative frequency of column B in group 2= $\frac{18}{32}=0.4375\approx0.44$

7 0

3 years ago