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marin [14]
3 years ago
6

How can I determine the line of best fit, and how will this help me to make predictions?

Mathematics
2 answers:
HACTEHA [7]3 years ago
4 0

Answer:

A line of best fit can be roughly determined using an eyeball method by drawing a straight line on a scatter plot so that the number of points above the line and below the line is about equal (and the line passes through as many points as possible).

uysha [10]3 years ago
4 0

Answer: Draw a straight line on a scatter plot.

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3/4*x = 1/5<br> X=<br> A. 3 3/4<br> B. 11/20<br> C. 4/15<br> D. 3/20
Pepsi [2]
X = 1/5 ÷ 3/4
x = 1/5 × 4/3
x = 4/15

the answer is C
7 0
3 years ago
Read 2 more answers
__5. If the formula for the perimeter of a rectangle
yuradex [85]

Answer:

w=\frac{P-2l}{2} \textrm{ or } w=\frac{P}{2}-l

Step-by-step explanation:

Given:

The perimeter of a rectangle is given as,

P=2l+2w

We are asked to express this in terms of w.

Add -2l both sides and simplify. This gives,

P-2l=2l-2l+2w\\ P-2l=2w

Now, we divide both sides by 2 to get an expression in terms of w. This gives,

\frac{P-2l}{2}=\frac{2w}{2}\\ w=\frac{P-2l}{2} \textrm{ or}\\ w=\frac{P}{2}-l

7 0
3 years ago
The ratio of points scored by Jennie, Sarah, and Sadie in the basketball games played last week was 1:3:5. If jenny scored 10 po
VikaD [51]
<h2>|| <u>Question</u> ||</h2>

The ratio of points scored by Jennie, Sarah, and Sadie in the basketball games played last week was 1:3:5. If jenny scored 10 points last week, what was the total number of points scored by these three girls?

<h2>|| <u>Answer</u> ||</h2>

The ratio of points scored by Jennie, Sarah, and Sadie in the basketball games played last week was 1:3:5.

jenny scored 10 points last week game.

=> 1x, 3x, 5x.

=> 1(10), 3(10) , 5(10)

=> 10, 30, 50

Therefore, The points scored by Jennie, Sarah, and Sadie in the basketball game played last week was 10, 30, 50

The total number of points scored by these three girls are:- 10+30+50 = 90

8 0
3 years ago
A lot of 100 semiconductor chips contains 20 that are defective. (a) two are selected, at random, without replacement, from the
borishaifa [10]
Given: all selections are without replacement
Let D=event that chip is defective
N=event that chip is normal
note that D and N are complementary.
x=undefined event
(a) Second is defective
Probability for second chip to be defective
P(xD)=P(ND)+P(DD)
P(ND)=(80/100)*(20/99)=1600/9900
P(DD)=(20/100)*(19/99)=380/9900
=>
P(xD)=(1600+380)/9900=1980/9900=1/5

(b) All three are defective
P(DDD)=(20/100)*(19/99)*(18/98)=19/2695

Note: in probabilities, it is preferable to use the exact values (i.e. fractions).
6 0
4 years ago
Solve for x.<br> 5x - 5 = x + 15​
Nutka1998 [239]

x = 5

I hope this helped :D

5 0
3 years ago
Read 2 more answers
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