This question is really hard
15u²v³, 20u⁵v², 45u³v⁵
Our greatest common factor would be 5u²v²
Why?
Because 5u²v² goes into 15u²v³ , 20u⁵v² , 45u³v⁵ the maximum amount that it can.
15u²v³ ÷ 5u²v² = 3v
20u⁵v² ÷ 5u²v² = 4v³
45u³v⁵ ÷ 5u²v² = 9uv³
~Hope I helped!~
Answer:
D. 108 liters
Step-by-step explanation:
Given that the leak is ;
5 drops = 5 minutes
?= 4 weeks
Find number of hours in 4 weeks
1 week=7days
4 weeks=?--------------cross multiply
4×7=28 days
1 day=24 hours
28 days=?--------------cross multiply
28×24=672 hours
Hour= 60 minutes
672 hours=?
672×60=40320 minutes
Finding the leakage in 4 weeks
80 drops= 5 minutes
?=40320 minutes------------cross multiplication
(40320×80)÷5 =645120 drops
Finding the liters of water wasted in 4 weeks
60 drops of water= 10 milliliters
645120 drops of water=?-------------cross multiply
(645120×10)÷60 =107520 milliliters
But you know
1 milliliter=0.001 liters
107520 milliliters=?-----------cross multiply
107520×0.001
=107.52 liters
=108 liters
Answer: = y-6 / y+3
this is the answer hope i helped!!!!
Like 65112 idk i need more pointe