The big bang did not produce a significant proportion of elements heavier than helium because the temperatures and densities present in the early universe were not sufficient to support the fusion of heavier elements.
During the first few minute of the big bang, the universe was composed of mostly hydrogen and helium, with very small amounts of lithium and beryllium. As the universe expanded and cooled, the denser regions of the universe collapsed to form the first stars. Inside these stars, the intense pressure and heat generated by nuclear fusion reactions allowed for the production of heavier elements, such as carbon and oxygen. However, elements heavier than helium, such as iron and nickel, require even higher temperatures and densities to be produced, which can only be found in the cores of supernovae. Therefore, the big bang alone did not produce a significant proportion of elements heavier than helium.
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Depositional landforms are the visible evidence of processes that have deposited sediments or rocks after they were transported by flowing ice or water, wind or gravity. Examples include beaches, deltas, glacial moraines, sand dunes and salt domes
Answer: The statement is true
Explanation:
The half-life of a radioactive isotope is the time taken for half of the total number of atoms in a given sample of the isotope to decay.
For instance
The half-life of radium is 1622 years. This means that if we have 1000 radium atoms at the beginning, then at the end of 1622 years, 500 atoms would have disintegrated, leaving 500 undecayed radium atoms
Thus, the statement is true
Answer:
Oxidation is the loss of electrons, that is, addition of electronegetive elements, example is addition of oxygen. Also, removal of electropositive elements, example is removal of hydrogen.
Explanation: a) In the presence of excess oxygen, propane burns in air, which gives the following chemical equation:
C3H8 + 5O2⇒ 3CO2 + 4H2O +Heat
b) When insufficient oxygen or too much oxygen is present for complete combustion, the following equation is given:
2C3H8 + 9O2 ⇒ 4CO2 + 2CO + 8H2O + Heat
c) At the anode( negative terminal): O∧2- ⇒ O + e
Oxygen accepts electron.
d) At cathode ( positive terminal): H∧+ + e∧- ⇒ H
Hydrogen donates electron
d) Nernst equation for reversal potential is given as follows:
E= RT/zF In{ion outside cell}/{ion inside cell}= 2.303 RT/zF In{ion outside cell}/{ion inside cell}
Answer:
1134
Explanation:
(the ones place was rounded up). 1133.981 is the unrounded answer.
