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1 year ago

Why did the big bang not produce a significant proportion of elements heavier than helium?

1 answer:

7 0

The big bang did not produce a significant proportion of elements heavier than helium because the temperatures and densities present in the early universe were not sufficient to support the fusion of heavier elements.

During the first few minute of the big bang, the universe was composed of mostly hydrogen and helium, with very small amounts of lithium and beryllium. As the universe expanded and cooled, the denser regions of the universe collapsed to form the first stars. Inside these stars, the intense pressure and heat generated by nuclear fusion reactions allowed for the production of heavier elements, such as carbon and oxygen. However, elements heavier than helium, such as iron and nickel, require even higher temperatures and densities to be produced, which can only be found in the cores of supernovae. Therefore, the big bang alone did not produce a significant proportion of elements heavier than helium.

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How many milliliters of 2.19 M H2SO4 are required to react with 4.75 g of solid containing 21.6 wt% Ba(NO3)2 if the reaction is

Setler [38]

Answer:

1.7927 mL

Explanation:

The mass of solid taken = 4.75 g

This solid contains 21.6 wt% $Ba(NO_3)_2$ , thus,

Mass of $Ba(NO_3)_2$ = $\frac {21.6}{100}\times 4.75\ g$ = 1.026 g

Molar mass of $Ba(NO_3)_2$ = 261.337 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{1.026\ g}{261.337\ g/mol}$

$Moles= 0.003926\ mol$

Considering the reaction as:

$Ba(NO_3)_2+H_2SO_4\rightarrow BaSO_4+2HNO_3$

1 moles of $Ba(NO_3)_2$ react with 1 mole of $H_2SO_4$

Thus,

0.003926 mole of $Ba(NO_3)_2$ react with 0.003926 mole of $H_2SO_4$

Moles of $H_2SO_4$ = 0.003926 mole

Also, considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Molarity = 2.19 M

So,

$2.19=\frac{0.003926}{Volume\ of\ the\ solution(L)}$

Volume = 0.0017927 L

Also, 1 L = 1000 mL

So, volume = 1.7927 mL

5 0

3 years ago

How many moles are in 5.025 grams of NaOH?

yKpoI14uk [10]

Answer:

The SI base unit for amount of substance is the mole. 1 grams NaOH is equal to 0.025001806380511 mole.

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3 years ago

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stepladder [879]

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3 years ago

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Yuri [45]

Answer:

Your answer is A. They will show even dispersion to get water.

Explanation:

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4 years ago

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