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Nesterboy [21]
1 year ago
11

Why did the big bang not produce a significant proportion of elements heavier than helium?

Chemistry
1 answer:
Travka [436]1 year ago
7 0

The big bang did not produce a significant proportion of elements heavier than helium because the temperatures and densities present in the early universe were not sufficient to support the fusion of heavier elements.

During the first few minute of the big bang, the universe was composed of mostly hydrogen and helium, with very small amounts of lithium and beryllium. As the universe expanded and cooled, the denser regions of the universe collapsed to form the first stars. Inside these stars, the intense pressure and heat generated by nuclear fusion reactions allowed for the production of heavier elements, such as carbon and oxygen. However, elements heavier than helium, such as iron and nickel, require even higher temperatures and densities to be produced, which can only be found in the cores of supernovae. Therefore, the big bang alone did not produce a significant proportion of elements heavier than helium.

to know more about compounds-

brainly.com/question/12166462

#SPJ4

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Please help me with chem, it would be very appreciated!
Lelu [443]

To determine the shapes of molecules, we must become acquainted with the Lewis electron dot structure. Although the Lewis theory does not determine the shapes of molecules, it is the first step in predicting shapes of molecules. The Lewis structure helps us identify the bond pairs and the lone pairs.

Please mark BRAINLIEST.

5 0
3 years ago
How many inches are in 2.0 miles
erastovalidia [21]
126,720 inches are in 2.0 miles
3 0
3 years ago
Would Li CO2 and LiOH produce the same colors? Explain your thinking.
saul85 [17]

Answer:

Lithium hydroxide is a base.

Carbon dioxide is the anhydride of the carbonic acid, H₂CO₃.

Therefore, the reaction awaited is a typical neutralization reaction with the formation of a salt and water.

2LiOH + CO₂ → Li₂CO₃ + H₂O

So, 2*20 = 40 moles of LiOH react with 20 moles of CO₂.

Molar Mass of LiOH = 23.95 g/mol

So, 40 * 23.95 = 958 g

8 0
1 year ago
6. (1 point) What is the correct formula for sodium sulfate? *
Deffense [45]
6) Na2 SO4
7)nonmetallic elements
10)mass
11) mole
* sorry I didn't know Q. 8/9
4 0
3 years ago
Read 2 more answers
Urea (CH4N2O) is a common fertilizer that can be synthesized by the reaction of ammonia (NH3) with carbon dioxide as follows: 2N
Lera25 [3.4K]

Answer:

NH3

Explanation:

2NH3(aq)+CO2(aq)→CH4N2O(aq)+H2O(l)

So for two moles of NH3 we need one mole of CO2. So let's count moles for each reagent.

n(NH3)=m(NH3)/M(NH3)=135700/17,03=7968.29 mol

n(CO2)=m(CO2)/M(CO2)=211400/44.01=4803.45 mol

From equation we have to divide n(NH3) by 2 because we need two equivalent per one CO2. That will be 3984.145. So the limiting agent is NH3 because it's not enough of it to react with all CO2

4 0
3 years ago
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