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Jlenok [28]
3 years ago
10

Match each power of i with its multiplicative inverse.

Mathematics
2 answers:
julia-pushkina [17]3 years ago
4 0

Answer:

  1. i=\frac{1}{i}*\frac{-i}{-1}=-i
  2. i^2=\frac{1}{i^2}*\frac{-i^2}{-i^2}=-1
  3. i^3=\frac{1}{i^3}*\frac{-i^3}{-i^3}=i
  4. i^4=\frac{1}{i^4}*\frac{-i^4}{-i^4}=1

Step-by-step explanation:

To find the multiplicative inverse of a complex number, you do as follows:

The inverse is found by reciprocating the original complex number. (\frac{1}{complex number}) Multiply the numerator and denominator of the reciprocal by conjugate of the denominator and simplify.

<em>Hope this helps!!</em>

erastovalidia [21]3 years ago
3 0

By definition we have to:
 In mathematics, the inverse multiplicative, reciprocal or inverse of a non-zero number x, is the number, denoted as 1/x or x -1, which multiplied by x gives 1.
 We have then:

 1) i
 The multiplicative inverse is:
 \frac{1}{i}
 Rewriting we have:
 \frac{1}{i} \frac{i}{i}
 \frac{i}{i^2}
 \frac{i}{-1}
 -i
 Answer 3) -i

 2) i^2
 The multiplicative inverse is:
 \frac{1}{i^2}
 Rewriting we have:
 \frac{1}{-1}
 -1
 Answer 4) -1

 3) i^3
 The multiplicative inverse is:
 \frac{1}{i^3}
 Rewriting we have:
 \frac{1}{i*i^2}
 \frac{1}{i^2}*\frac{1}{i}
 \frac{1}{-1}*\frac{1}{i}*\frac{i}{i}
 (-1)*\frac{i}{i^2}
 (-1)* \frac{i}{-1}
 i
 Answer 1) i

 4) i^4
 The multiplicative inverse is:
 \frac{1}{i^4}
 Rewriting we have:
 \frac{1}{i^2i^2}
 \frac{1}{(-1)(-1)}
 \frac{1}{1}
 1
 Answer 2) 1
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Answer:

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C is the correct option.

Step-by-step explanation:

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