It seems it should be the other way... . How soon will the puppy catch up with the kitten.
The way you have it the kitten will never catch the pup. There is already 180m between them so, the distance will only increase because the puppy runs faster than the cat.
If the puppy runs after the cat, will eventually catch up with it and can be calculated. Not the other way around.
If the pup runs after the cat, the distance between them will decrease and the pup will catch the cat.
RT = D kitten
RT = D+180 puppy
20T = D
25T = D + 180
Substitution
25T = 20T +180
5T = 180
T = 36s
Answer:
"demand"
Step-by-step explanation:
Vocabulary question.
"Demand" refers to the quantity of goods and services that consumers are willing to buy at a given price.
Answer:
A
Step-by-step explanation:
6/24 multiplied by 5/24
Since f(x) is (strictly) increasing, we know that it is one-to-one and has an inverse f^(-1)(x). Then we can apply the inverse function theorem. Suppose f(a) = b and a = f^(-1)(b). By definition of inverse function, we have
f^(-1)(f(x)) = x
Differentiating with the chain rule gives
(f^(-1))'(f(x)) f'(x) = 1
so that
(f^(-1))'(f(x)) = 1/f'(x)
Let x = a; then
(f^(-1))'(f(a)) = 1/f'(a)
(f^(-1))'(b) = 1/f'(a)
In particular, we take a = 2 and b = 7; then
(f^(-1))'(7) = 1/f'(2) = 1/5
