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3 years ago

What is the equation of the line shown?

Mathematics

1 answer:

nasty-shy [4]3 years ago

3 0

Answer:

y=1/2x+2

Step-by-step explanation:

You might be interested in

The square of five is

Mars2501 [29]

Square of five = 5^2 = 5 x 5 = 25

answer
c) 25

6 0

3 years ago

I need help if you get it right I will mark you

pav-90 [236]

Answer:

%30 off is the better price

Step-by-step explanation:

firstly we know that 2 - 12 is equal to 10 so that is $10.00 there from that coupon

to find out the second value, we first devide by the total amount (%100 in this case)

12 / 100 = 10.12

then we multiply by the partial amount (%30)

0.12 * 30 = 3.6

convert that into a dollar amount and we get the total discount in dollars

3.60 = $3.60

AND

$3.60 > $2.00

hope this helps ya, take care mate :D

6 0

3 years ago

Read 2 more answers

Jose earns $3680 per month of which 22% is taken out his paycheck for federal and state income taxes and other required deductio

Lady bird [3.3K]

Answer: Jose earns $169.89

Step-by-step explanation:I’m still trying to learn the step by step

4 0

3 years ago

angel's dad bought a television for her completing all of her digital learning day lesson. he want to warp the gift. the box mea

atroni [7]

Answer: 13 sheets of paper

Step-by-step explanation:

We are given the dimensions of the box and the wrap paper:

Box:

$(56 in)(8 in)(36 in)$

Warp paper:

$(26 in)(17 in)$

Now we need to find the surface area of the box and the area of the wrap paper:

Box:

$surface_{1}=(56 in)(8 in)(2)=896 in^{2}$

$surface_{2}=(8 in)(36 in)(2)=576 in^{2}$

$surface_{3}=(56 in)(36 in)(2)=4032 in^{2}$

$surface-area=896 in^{2}+576 in^{2}+4032 in^{2}=5504 in^{2}$

Warp paper:

$area=(26 in)(17 in)=442 in^{2}$

Dividing the area of the box by the area of the paper:

$\frac{surface-area}{area}=\frac{5504 in^{2}}{442 in^{2}}=12.45 \approx 13$

This means Angel's dad needs to purchase 13 sheets of wrapping paper.

4 0

3 years ago

If A and B are independent events with P(A) = .5 and P(B) = .2, find the following:a) P(A U B)b) P(A^c ? B^c)c) P(A^c U B^c)**No

Effectus [21]

If A and B are independent, then $P(A\cap B)=P(A)P(B)$ .

$P(A\cup B)=P(A)+P(B)-P(A\cap B)=P(A)+P(B)-P(A)P(B)$

$P(A\cup B)=0.5+0.2-0.5\cdot0.2$

$\boxed{P(A\cup B)=0.6}$

b. I'm guessing the ? is supposed to stand for intersection. We can use DeMorgan's law for complements here:

$P(A^c\cap B^c)=P(A\cup B)^c=1-P(A\cup B)$

$P(A^c\cap B^c)=1-0.6$

$\boxed{P(A^c\cap B^c)=0.4}$

c. DeMorgan's law can be used here too:

$P(A^c\cup B^c)=P(A\cap B)^c=1-P(A\cap B)=1-P(A)P(B)$

$P(A^c\cup B^c)=1-0.5\cdot0.2$

$\boxed{P(A^c\cup B^c)=0.9}$

4 0

3 years ago