<h3>
Answer: -35</h3>
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Explanation:
Let y = -3*f(-3) + 2*f(3)
The goal is to find the value of y as some single numeric value.
We know that f(x) is an odd function. This means that
f(-x) = -f(x)
For all x in the domain of f(x).
Based on that, we can say
f(-3) = -f(3)
and,
y = -3*f(-3) + 2f(3)
-1*y = -1*(-3*f(-3) + 2*f(3)) ... multiply both sides by -1
-y = 3*f(-3) - 2*f(3)
-y = 3*f(-3) + 2*(-f(3))
-y = 3*f(-3) + 2*f(-3)
-y = 3*7 + 2*7 .... f(-3) replaced with 7
-y = 21+14
-y = 35
y = -35
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Here's a slightly different approach
f(-3) = 7
-f(3) = 7
Since f(-3) = -f(3)
We can then transform -f(3) = 7 into f(3) = -7 after multiplying both sides by -1
Therefore,
y = -3*f(-3) + 2f(3)
y = -3*7 + 2(-7)
y = -21 - 14
y = -35
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There are probably other routes to solve this problem.
Whichever path you take, you should find that -3*f(-3) + 2f(3) = -35
Answer:
9
Step-by-step explanation:
9 x 9 = 81
Thanks for the points ur so kinds
Answer:
(B) ![\dfrac{3}{1}](https://tex.z-dn.net/?f=%5Cdfrac%7B3%7D%7B1%7D)
Step-by-step explanation:
Given a point
on the line segment BD, the internal division formula is given by:
![C(x,y)=(\dfrac{mx_2+nx_1}{m+n} ,\dfrac{my_2+ny_1}{m+n} )\\\\(x_1,y_1)=B(0, 1)$ and (x_2,y_2)=D(4, 1)\\](https://tex.z-dn.net/?f=C%28x%2Cy%29%3D%28%5Cdfrac%7Bmx_2%2Bnx_1%7D%7Bm%2Bn%7D%20%2C%5Cdfrac%7Bmy_2%2Bny_1%7D%7Bm%2Bn%7D%20%29%5C%5C%5C%5C%28x_1%2Cy_1%29%3DB%280%2C%201%29%24%20and%20%28x_2%2Cy_2%29%3DD%284%2C%201%29%5C%5C)
Therefore:
![C(3,1)=(\dfrac{m*4+n*0}{m+n} ,\dfrac{m*1+n*1}{m+n} )\\C(3,1)=(\dfrac{4m}{m+n} ,\dfrac{m+n}{m+n} )\\$Therefore:\\\dfrac{4m}{m+n}=3\\4m=3(m+n)\\4m=3m+3n\\4m-3m=3n\\m=3n\\$Divide both sides by n$\\\dfrac{m}{n}= \dfrac{3}{1}](https://tex.z-dn.net/?f=C%283%2C1%29%3D%28%5Cdfrac%7Bm%2A4%2Bn%2A0%7D%7Bm%2Bn%7D%20%2C%5Cdfrac%7Bm%2A1%2Bn%2A1%7D%7Bm%2Bn%7D%20%29%5C%5CC%283%2C1%29%3D%28%5Cdfrac%7B4m%7D%7Bm%2Bn%7D%20%2C%5Cdfrac%7Bm%2Bn%7D%7Bm%2Bn%7D%20%29%5C%5C%24Therefore%3A%5C%5C%5Cdfrac%7B4m%7D%7Bm%2Bn%7D%3D3%5C%5C4m%3D3%28m%2Bn%29%5C%5C4m%3D3m%2B3n%5C%5C4m-3m%3D3n%5C%5Cm%3D3n%5C%5C%24Divide%20both%20sides%20by%20n%24%5C%5C%5Cdfrac%7Bm%7D%7Bn%7D%3D%20%5Cdfrac%7B3%7D%7B1%7D)
Therefore the fraction which compares BC to BD is ![\dfrac{3}{1}](https://tex.z-dn.net/?f=%5Cdfrac%7B3%7D%7B1%7D)
15.5:1
62/4 = 15.5
15.5 : 1