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Pepsi [2]
3 years ago
6

-8y^3( 7y^2- 4y - 11)How do you Factor this?

Mathematics
1 answer:
marshall27 [118]3 years ago
8 0

-8y^3( 7y^2- 4y - 11)

-8y^3 (7y-11) (y+1)

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For f(x) = 5x + 1
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Answer:

A. f(7) = 5(7) + 1\\\\f(7) = 36

B. f^{-1}(x) = \frac{x - 1}{5}

C. f^{-1}(7) =\frac{6}{5}

D. f(\frac{6}{5}) = 7

Step-by-step explanation:

A. To solve the first part of the problem we must replace x = 7 in the function f(x) = 5x + 1

So:

f(7) = 5(7) + 1\\\\f(7) = 36

B. In part B we must find the inverse function of f(x) = 5x + 1

To find the inverse function do y = f(x)

y = 5x +1

Now clear the variable x.

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f^{-1}(x) = \frac{x - 1}{5}

C. Now we take the inverse function found above and replace x = 7

f^{-1}(7) = \frac{7 - 1}{5}\\\\f(7) = \frac{6}{5}

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x = f( f^{-1}(7))\\\\f^{-1}(7) = \frac{6}{5}\\\\ x= f(\frac{6}{5} )\\\\f(\frac{6}{5}) = 5(\frac{6}{5}) + 1\\\\f(\frac{6}{5}) = 7

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