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Nimfa-mama [501]

3 years ago

11

Draw a line segment PQ of length 8cm. Find 1/4 of PQ using compass.

2 answers:

Tcecarenko [31]3 years ago

8 0

Answer:

idk

Step-by-step explanation:

gtnhenbr [62]3 years ago

7 0

To help you answer: think about what makes a fourth. If you have a rectangular cake, how do you split it into four pieces?

To do so with the compass however, remember that the joining the points of intersection of intersecting circles with the same radius creates a perpendicular bisector.

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Simplify the expression.<br> 3 - 4 +7 - 4

Tresset [83]

2
3+7=10
-4-4=-8
10-8=2

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Which expression represents the following algebraic statement?

Nat2105 [25]

The first one, 7x-2y

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3 years ago

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Solve and check: 1 x + 3 = x + 10 x − 2 From least to greatest, the solutions are x = and x = .

blondinia [14]

Answer:

x= 1/2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

1x+3=x+10x−2

x+3=x+10x+−2

x+3=(x+10x)+(−2)(Combine Like Terms)

x+3=11x+−2

x+3=11x−2

Step 2: Subtract 11x from both sides.

x+3−11x=11x−2−11x

−10x+3=−2

Step 3: Subtract 3 from both sides.

−10x+3−3=−2−3

−10x=−5

Step 4: Divide both sides by -10.

−10x/−10=−5/−10x=1/2

8 0

3 years ago

Read 2 more answers

PLEASE HELP ME:<br><br> Find the perimeter of the figure. Round to the nearest tenth.

Ksenya-84 [330]

Answer:

perimeter = 20.9 units

Step-by-step explanation:

perimeter

perimeter = distance around two dimensional shape

= addition of all sides lengths

<h2>perimeter of the figure</h2><h2>= AB+BC+CD+AD</h2>

distance formula:

$d = \sqrt{( x_{2} - x_{1}) {}^{2} + ( y_{2} - y_{1}) {}^{2} }$

<h3>1) distance of AB</h3>

A(-3,0) B(2,4)

x1 = -3 x2 = 2

y1 = 0 y2 = 4

(substitute the values into the distance formula)

$ab = \sqrt{(2 - ( - 3)) {}^{2} + (4 - 0) {}^{2} }$

$ab = \sqrt{5 {}^{2} + 4 {}^{2} }$

$ab = \sqrt{41}$ AB = 6.4 units

<h3>2) distance of BC</h3>

B(2,4) C(3,1)

x1 = 2 x2 = 3

y1 = 4 y2 = 1

$bc = \sqrt{(3 - 2) {}^{2} + (1 - 4) {}^{2} }$

$bc = \sqrt{1 {}^{2} + ( - 3) {}^{2} }$

$bc = \sqrt{10}$

BC = 3.2 units

<h3>3) distance of CD</h3>

C(3,1) D(-4,-3)

x1 = 3 x2 = -4

y1 = 1 y2 = -3

$cd = \sqrt{( - 4 - 3) {}^{2} + ( - 3 - 1)) {}^{2} }$

$cd = \sqrt{( - 7) {}^{2} + ( - 4 ){}^{2} }$

$cd = \sqrt{65}$

CD = 8.1 units

<h3>4) distance of AD</h3>

A(-3,0) D(-4,-3)

x1 = -3 x2 = -4

y1 = 0 y2 = -3

$ad = \sqrt{( - 4 - ( - 3)) {}^{2} + ( - 3 - 0) {}^{2} }$

$ad = \sqrt{( - 1) {}^{2} + ( - 3) {}^{2} }$

$ad = \sqrt{10}$

AD = 3.2 units

<h2>perimeter of figure</h2>

= AB+BC+CD+AD

= 6.4 + 3.2 + 8.1 + 3.2

= 20.9 units

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