The parent function is either identity function or constant function
the translation is down 6
Answer:
isoceles but not equilateral
Step-by-step explanation:
it has two sides that are the same length, but not all three sides are the same length
An equilateral triangle is therefore a special case of an isosceles triangle having not just two, but all three sides equal
For this translation, you need to replace every occurrence of "x" with "x-3", and every occurrence of "y" with "y+5".
The perimeter, by definition, is the outside measure of that figure. MN and LM are the same length and LK and NK are the same length....we just need to find the lengths! Use the distance formula to find the distance between the 2 points:
![\sqrt{( x_{2} - x_{1} ) ^{2} +( y_{2}- y_{1} ) ^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%7B%28%20x_%7B2%7D%20-%20x_%7B1%7D%20%29%20%5E%7B2%7D%20%2B%28%20y_%7B2%7D-%20y_%7B1%7D%20%29%20%5E%7B2%7D%20%20%7D%20)
For the segment MN, use the coordinates of M as your x1, y1, and use the coordinates of N for x2, y2:
![\sqrt{(3-2) ^{2}+(4-3) ^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%7B%283-2%29%20%5E%7B2%7D%2B%284-3%29%20%5E%7B2%7D%20%20%7D%20)
which simplifies to
![\sqrt{(1 )^{2}+(1) ^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%7B%281%20%29%5E%7B2%7D%2B%281%29%20%5E%7B2%7D%20%20%7D%20)
which is
![\sqrt{2}](https://tex.z-dn.net/?f=%20%5Csqrt%7B2%7D%20)
So that is the length of both MN and LM. So far our perimeter is
![\sqrt{2} + \sqrt{2}=2 \sqrt{2}](https://tex.z-dn.net/?f=%20%5Csqrt%7B2%7D%20%2B%20%5Csqrt%7B2%7D%3D2%20%5Csqrt%7B2%7D%20%20)
Now let's use the same formula to find out the length of one of the longer segments:
![\sqrt{(5-3) ^{2} +(3-2) ^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%7B%285-3%29%20%5E%7B2%7D%20%2B%283-2%29%20%5E%7B2%7D%20%7D%20)
which simplifies down to
![\sqrt{(2) ^{2} +(1) ^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%7B%282%29%20%5E%7B2%7D%20%2B%281%29%20%5E%7B2%7D%20%7D%20)
which is of course
![\sqrt{5}](https://tex.z-dn.net/?f=%20%5Csqrt%7B5%7D%20)
Since we have 2 of those lengths,
![\sqrt{5} + \sqrt{5}=2 \sqrt{5}](https://tex.z-dn.net/?f=%20%5Csqrt%7B5%7D%20%2B%20%5Csqrt%7B5%7D%3D2%20%5Csqrt%7B5%7D%20%20)
So our perimeter is, in the end,
![2 \sqrt{2}+2 \sqrt{5}](https://tex.z-dn.net/?f=2%20%5Csqrt%7B2%7D%2B2%20%5Csqrt%7B5%7D%20%20)
That's the third choice down