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muminat
3 years ago
15

What is the number of distinguishable letters in the word alphabet

Mathematics
1 answer:
Rainbow [258]3 years ago
4 0
First, we have to find how many different letters does the world alphabet have, we are not going to count the letters that repeat.
It has 7 different letters (not 8, because the letter "A" appears two times.
The formula would be:
P=7!
P=7*6*5*4*3*2*1
P=5,040
That's your answer!
You might be interested in
Help please mathematics 22 -24
Pavel [41]

Answer:  (22) $9,075     (23) $656.25      (24) $217.13

<u>Step-by-step explanation:</u>

Cost Function: C(x) = 5.75x + 8,000

              C(10,000) = 5.75(10,000) + 8,000

                                = 57,500     + 8,000

                                = 65,500

Revenue Function: R(x) = 9.50x

                        R(7,850) = 9.50(7,850)

                                       =    74,575

Profit Function: P(x) = R(x) - C(x)

                                 = 74,575 - 65,500

                                 = 9,075

*****************************************************************************

Retail = Unit Cost + Unit Cost × Markup

         =     $375    +         $375 × .75

         =     $375    +           $281.25

         =     $656.25

*****************************************************************************

$225 but if paid within 10 days there is a 3.5% discount

Discount = $225 - $225 × .035

               =  $225 -     $7.88

               =  $217.13

8 0
3 years ago
What function corresponds to the ordered pairs shown in the table?
Anettt [7]

well, we know it's a line, and to get the equation of any line all we need is two points, let's pick two from the table hmmmm say let's use (-3 , -7) and (3 , 11)

(\stackrel{x_1}{-3}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{11}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{11}-\stackrel{y1}{(-7)}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{(-3)}}}\implies \cfrac{11+7}{3+3}\implies \cfrac{18}{6}\implies 3

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-7)}=\stackrel{m}{3}(x-\stackrel{x_1}{(-3)}) \\\\\\ y+7=3(x+3)\implies y+7=3x+9\implies y = 3x+2

6 0
3 years ago
Will mark brainliest plss
babymother [125]
X1 = 0
X2 = 1
X3 = 7

I hope that helps!! :)
6 0
2 years ago
Read 2 more answers
How to solve this problem​
nevsk [136]

Let C be the center of the circle. The measure of arc VSU is 2+114x, so the measure of the minor arc VU is 360-(2+114x)=358-114x. The central angle VCU also has measure 358-114x.

Triangle CUV is isosceles, so the angles CVU and CUV are congruent. The interior angles of any triangle are supplementary (they add to 180 degrees) so

m\angle VCU+2m\angle CUV=180

\implies m\angle CUV=\dfrac{180-(358-114x)}2=57x-89

UT is tangent to the circle, so CU is perpendicular to UT. Angles CUV and VUT are complementary, so

(57x-89)+(31x+3)=90

\implies88x=176

\implies x=2

So finally,

m\widehat{VSU}=2+114\cdot2=230

degrees.

6 0
3 years ago
Plz help I only got until 5:00 today
katen-ka-za [31]

The correct answer is -9/22.

6 0
3 years ago
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