the answer is c you just have to solve each one
Answer:
what you want help with?
Step-by-step explanation:
There's no such thing as parallel or perpendicular "to a point". A problem like that
will always want the new line to be parallel or perpendicular to another <em><u>line</u></em>.
-- If the new line is parallel to the given line, then they have the <em><u>same</u></em> slope.
-- If the new line is perpendicular to the the given line, then the slope of the
new line is [ <em><u>1 / slope of the given line</u></em> ].
In either case, you now have the slope of the new line and a point on it.
From there, you should have no trouble finding its equation.
Answer:
see explanation
Step-by-step explanation:
Since AC = BC then ΔABC is isosceles with base angles
∠BAC =∠ABC, thus
3x + x = 70
4x = 70 ( divide both sides by 4 )
x = 17.5
----------------------------------------------------
∠ADC is an external angle of ΔABD and the external angle is equal to the 2 opposite interior angles, hence
y = 70 + x = 70 + 17.5 = 87.5
