Please help me ill give brainiest
1 answer:
You might be interested in
The equation of the mirror line in standard form is: 10y+12x=39. The reflection of the point is A'(1,2)
Step-by-step explanation:
Given that the endpoints of the segments are: (5,4) and (-1,-1) then the equation of the mirror line will be;
slope=m=Δy/Δx
Δy= -1 - 4= -5
Δx= -1-5 = -6
m= -5/-6 = 5/6
For the equation, taking point (5,4), and (x,y), it will be;
m=Δy/Δx
5/6= y-4/x-5
5(x-5) = 6(y-4)
5x-25 =6y-24
5x=6y-24+25
5x=6y+1
5x-1=6y
6y=5x-1 -------divide both sides by 6
y=5/6x -1/6 -------Equation of line segment
The mirror line is a perpendicular bisector of the segment.This means it passes at the midpoint of the segment.
Finding the midpoint of the segment will be;
{(x₁+x₂)/2 ,(y₁+y₂)/2}
{(5+-1)/2, (4+-1)/2} =(4/2, 3/2) =(2, 3/2)
Using the coordinate point of the midpoint, you can find the equation of the mirror line knowing that the slope will be -6/5 because the mirror line is perpendicular to the line segment that has a slope of 5/6.
Finding the equation of the mirror line using point (2, 3/2), (x,y) and m= -6/5
The equation of the mirror line in standard form is;
10y+12x=39
2. Given point A(3,-2) and line y=1/2x -1 ,you can use a graph tool to plot the equation for the mirror line, plot the object point and locate the image point across the mirror line.
From the graph, the image is A'(1,2)
Learn More
Reflection of a point :brainly.com/question/12865568
Keywords : equation, mirror line, segment, endpoints, reflection
#LearnwithBrainly
