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Whitepunk [10]
3 years ago
6

5x4-2+x= 3937/993x9374

Mathematics
1 answer:
jonny [76]3 years ago
6 0

the answer would be x=−0.870452,0.712370

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Need help understanding what to do
Juliette [100K]
I believe you are expected to simplify. To do this all you do is group like terms (x, x², x³ etc.) and then simplify the coefficients. 

13. 10z + 7z - 19z² - 5z² - 17z 

first you can rearrange and group like terms (remember the bring the sign in front of each term with it). I would do it like this: 
-19z² - 5z² +10z + 7z - 17z

Now simplify the coefficients: 

-24z² + 0z 

you can omit the 0z and your simplified answer is 

-24z²

Main thing to remember here is that z and z² cannot be simplified together, nor can any variable that has an exponent because the exponent makes them differ. 

6 0
3 years ago
A line segment has endpoint j(2,4) and l(6,8).the point k is the midpoint of jl.what is an equation of a line perpendicular to j
GenaCL600 [577]
The equation of the line is:
 y-yo = m (x-xo)
 Where,
 m = (y2-y1) / (x2-x1)
 Substituting values:
 m = (8-4) / (6-2)
 m = (4) / (4)
 m = 1
 Then, the equation is:
 y-4 = 1 * (x-2)
 Rewriting:
 y = x-2 + 4
 y = x + 2
 The midpoint is:
 k = ((x1 + x2) / 2, (y1 + y2) / 2)
 k = ((2 + 6) / 2, (4 + 8) / 2)
 k = ((8) / 2, (12) / 2)
 k = (4, 6)
 Then, the equation of the perpendicular line that passes through k is:
 y = -x + b
 Looking for b we have:
 6 = -4 + b
 b = 6 + 4
 b = 10
 Substituting:
 y = -x + 10
 Answer:
 An equation of a line perpendicular to jl and passing through k is:
 y = -x + 10
3 0
3 years ago
Hello help me with this question thanks in advance​
Ede4ka [16]

\bold{\huge{\green{\underline{ Solutions }}}}

<h3><u>Answer </u><u>1</u><u>1</u><u> </u><u>:</u><u>-</u></h3>

<u>We </u><u>have</u><u>, </u>

\sf{HM = 5 cm }

  • <u>In </u><u>square </u><u>all </u><u>sides </u><u>of </u><u>squares </u><u>are </u><u>equal </u>

<u>The </u><u>perimeter </u><u>of </u><u>square </u>

\sf{ = 4 × side }

\sf{ = 4 × 5 }

\sf{ = 20 cm }

Thus, The perimeter of square is 20 cm

Hence, Option C is correct .

<h3><u>Answer </u><u>1</u><u>2</u><u> </u><u>:</u><u>-</u></h3>

<u>We </u><u>have</u><u>, </u>

\sf{MX  = 3.5 cm }

  • <u>In </u><u>square</u><u>,</u><u> </u><u>diagonals </u><u>are </u><u>equal </u><u>and </u><u>bisect </u><u>each </u><u>other </u><u>at </u><u>9</u><u>0</u><u>°</u>

<u>Here</u><u>, </u>

\sf{MX  = MT/2}

\sf{MT = 2 * 3.5 }

\sf{MT = 7 cm}

Thus, The MT is 7cm long

Hence, Option C is correct .

<h3><u>Answer </u><u>1</u><u>3</u><u> </u><u>:</u><u>-</u><u> </u></h3>

<u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>measure </u><u>of </u><u>Ang</u><u>l</u><u>e</u><u> </u><u>MAT</u>

  • <u>All </u><u>angles </u><u>of </u><u>square </u><u>are </u><u>9</u><u>0</u><u>°</u><u> </u><u>each </u>

<u>From </u><u>above </u>

\sf{\angle{MAT  = 90° }}

Thus, Angle MAT is 90°

Hence, Option B is correct .

<h3><u>Answer </u><u>1</u><u>4</u><u> </u><u>:</u><u>-</u></h3>

<u>We </u><u>know </u><u>that</u><u>, </u>

  • <u>All </u><u>the </u><u>angles </u><u>of </u><u>square </u><u>are </u><u>equal </u><u>and </u><u>9</u><u>0</u><u>°</u><u> </u><u>each </u>

<u>Therefore</u><u>, </u>

\sf{\angle{MHA  = }}{\sf{\angle{ MHT/2}}}

\sf{\angle{MHA = 90°/2}}

\sf{\angle {MHA = 45°}}

Thus, Angle MHA is 45°

Hence, Option A is correct

<h3><u>Answer </u><u>1</u><u>5</u><u> </u><u>:</u><u>-</u><u> </u></h3>

Refer the above attachment for solution

Hence, Option A is correct

<h3><u>Answer </u><u>1</u><u>6</u><u> </u><u>:</u><u>-</u><u> </u></h3>

Both a and b

  • <u>The </u><u>median </u><u>of </u><u>isosceles </u><u>trapezoid </u><u>is </u><u>parallel </u><u>to </u><u>the </u><u>base</u>
  • <u>The </u><u>diagonals </u><u>are </u><u>congruent </u>

Hence, Option C is correct

<h3><u>Answer </u><u>1</u><u>7</u><u> </u><u>:</u><u>-</u></h3>

In rhombus PALM,

  • <u>All </u><u>sides </u><u>and </u><u>opposite </u><u>angles </u><u>are </u><u>equal </u>

Let O be the midpoint of Rhombus PALM

<u>In </u><u>Δ</u><u>OLM</u><u>, </u><u>By </u><u>using </u><u>Angle </u><u>sum </u><u>property </u><u>:</u><u>-</u>

\sf{35° + 90° + }{\sf{\angle{ OLM = 180°}}}

\sf{\angle{OLM = 180° - 125°}}

\sf{\angle{ OLM = 55° }}

<u>Now</u><u>, </u>

\sf{\angle{OLM = }}{\sf{\angle{OLA}}}

  • <u>OL </u><u>is </u><u>the </u><u>bisector </u><u>of </u><u>diagonal </u><u>AM</u>

<u>Therefore</u><u>, </u>

\sf{\angle{ PLA = 55° }}

Thus, Angle PLA is 55° .

Hence, Option C is correct

8 0
2 years ago
Peyton needed to get her computer fixed. She took it to the repair store. The
Lelu [443]

Answer:

The cost of labor per hour is $105.

The expression is 4x + 77 = 497

Step-by-step explanation:

The expression is 4x + 77 = 497, where 4x represents the cost of labor per hour, 77 is the cost of the parts, and 497 is the total.

4x + 77 = 497

4x + 77 - 77 = 497 -77

4x = 420

4x/4=420/4

x = 105

5 0
3 years ago
Solve<br>-6x^2 + 6 - 2x =x​
Tanzania [10]

Answer:

x1= -1-√17/4

x2= -1+√17/4

3 0
3 years ago
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