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Whitepunk [10]
4 years ago
6

5x4-2+x= 3937/993x9374

Mathematics
1 answer:
jonny [76]4 years ago
6 0

the answer would be x=−0.870452,0.712370

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Given centerB with m∠ABD = 95 degrees
kirill [66]

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It would be the fourth one to me Yw

Step-by-step explanation:

8 0
3 years ago
andres has 10 more goldfish than todd. Together,they have 50 goldfish.How many goldfish does each boy have?
Dmitry [639]
Let's go ahead and construct an equation to show this. Together, they have 50 goldfish. This can be represented as =50. 

Since we don't know how many Todd has, we're going to make a variable. We'll name it T, for Todd.

What about Andres? How many does he have? 10 more than Todd. Well, if Todd's amount is T, and Andres has 10 more, we can express that as T+10.

Now, just put the two pieces together! T+10=50. 

The next step is inverse operations. You want to find out how many T is, so you need to get rid of the 10. To take 10 away from something is doing what? Subtraction! Be warned, though; whatever you do to one side of the problem, you have to do to the other. 10-10 is 0, and 50-10 is 40. Since we took the 10 away and 50 is now 40, what you're left with is T=40.

Wait a second.. wasn't "T" Todd's amount? Yep! That means that Todd has 40 goldfish. And we already know that Andres has 10, so there's your answer!
3 0
3 years ago
Read 2 more answers
Use the Parabola tool to graph the quadratic functions.
OLEGan [10]

Step-by-step explanation:

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6 0
3 years ago
What is the inverse function of h(x)=-3/5x+1/2?​
viva [34]

Answer:

h−1(x)=−5x/3+5/6

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7 0
2 years ago
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4vir4ik [10]

Answer:

The height of the equilateral triangle is 5\sqrt{3}\ units

Step-by-step explanation:

we know that

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Remember that the height of an equilateral triangle bisects the base.

see the attached figure to better understand the problem

AB^2=AD^2+BD^2

substitute the given values

10^2=5^2+BD^2

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BD^2=100-25

BD^2=75

BD=\sqrt{75}\ units

simplify

BD=5\sqrt{3}\ units`

therefore

The height of the equilateral triangle is 5\sqrt{3}\ units

7 0
4 years ago
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