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V125BC [204]
3 years ago
9

What is the function rule for the line?

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
8 0

Answer:

y =2/3x -2

Step-by-step explanation:

The y intercept is -2

The slope is

m = (y2-y1)/ (x2-x1)

Using the points (0,-2) and  (3,0)

m = ( 0 - -2)/(3 -0)

    = (0+2)/(3-0)

   = 2/3

The slope intercept form is

y = mx+b where m is the slope and b is the y intercept

y =2/3x -2

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Answer: (a)350 + 0.05x ≥ 600 (b) $5000


Explanation:

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Let x the sales amount


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350 + 0.05x ≥ 600

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Acrosonic's production department estimates that the total cost (in dollars) incurred in manufacturing x ElectroStat speaker sys
il63 [147K]

Answer:

a)  P(x)=-0.042x^2+530x-18000

b)  P'(x)=-0.084x+530

c)

P'(4000)=194

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Step-by-step explanation:

a)

We know that Revenue is our total income and cost is our total cost. Thus, profit is what's left after cost is subtracted from Income (revenue). Thus, we can say:

P(x) = R(x) - C(x)

Finding Profit Function (P(x)):

P(x) = R(x) - C(x)\\P(x) = -0.042x^2+800x-(270x+18000)\\P(x)=-0.042x^2+800x-270x-18000\\P(x)=-0.042x^2+530x-18000

This is the profit function.

b)

The marginal profit is the profit earned when ONE ADDITIONAL UNIT of the product is sold. This is basically the rate of change of profit per unit. We find this by finding the DERIVATIVE of the Profit Function.

Remember the power rule for differentiation shown below:

\frac{d}{dx}(x^n)=nx^{n-1}

Now, we differentiate the profit function to get the marginal profit function (P'):

P(x)=-0.042x^2+530x-18000\\P'(x)=2(-0.042)x^1+530x^0-0\\P'(x)=-0.084x+530

This is the marginal profit function , P'.

c)

We need to find P'(4000) and P'(9500). So we basically put "4000" and "9500" in the marginal profit function's "x". The value is shown below:

P'(x)=-0.084x+530\\P'(4000)=-0.084(4000)+530\\P'(4000)=194

and

P'(x)=-0.084x+530\\P'(9500)=-0.084(9500)+530\\P'(9500)=-268

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