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3 years ago

7

A line must contain at least three points ?

2 answers:

postnew [5]3 years ago

8 0

Answer:

Through any three non-collinear points, there exists exactly one plane. A plane contains at least three non-collinear points. If two points lie in a plane, then the line containing them lies in the plane. If two planes intersect, then their intersection is a line.

Vaselesa [24]3 years ago

7 0

Answer:

A plane contains at least three non-collinear points. If two points lie in a plane, then the line containing them lies in the plane. If two planes intersect, then their intersection is a line.

Step-by-step explanation:

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The area of a rectangular painting is 1/6 square yard. The width is 2/3 yard. What is the length of the painting use the formula

STatiana [176]

The length of the painting is 1/4.

According to the statement

we have to find the length of the rectangular painting with the help of the given information.

So, For this purpose, we know that the

The given information is:

The area of a rectangular painting is 1/6 square yard. The width is 2/3 yard.

And we have to use the formula

Area = Length * Breadth

So, Substitute the values in it then solve

So,

Area = Length * Breadth

1/6= Length * 2/3

1/6 = 2L/3

1 = 12L/3

1 = 4L

L = 1/4.

The value of the length is 1/4.

So, The length of the painting is 1/4.

Learn more about area of a rectangle here

brainly.com/question/2607596

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4 0

2 years ago

Lester bought 6.73 pounds of bologna at the deli. Renee bought 1.41 pounds of bologna. How much more bologna did Lester buy than

atroni [7]

Answer:

5.32

Step-by-step explanation:

You would have to subtract 6.73-1.41.

5 0

3 years ago

Help me please, need this done now.

Nikolay [14]

simplifying $\frac{\sqrt{4}}{\sqrt[3]{4}}$ we get $4^{\frac{1}{6}}$

Option B is correct.

Step-by-step explanation:

We need to simplify: $\frac{\sqrt{4}}{\sqrt[3]{4}}$

Solving:

$\frac{\sqrt{4}}{\sqrt[3]{4}}$

We know that √ = 1/2 and ∛=1/3

$\frac{4^{\frac{1}{2}}}{4^{\frac{1}{3}}}$

Applying exponent rule: $\frac{x^a}{x^b}=x^{a-b}$

$=4^{\frac{1}{2}-\frac{1}{3}}\\=4^{\frac{3-2}{6}}\\=4^{\frac{1}{6}}$

So, simplifying $\frac{\sqrt{4}}{\sqrt[3]{4}}$ we get $4^{\frac{1}{6}}$

Option B is correct.

Keywords: Solving Exponents

Learn more about Solving Exponents at:

#learnwithBrainly

6 0

3 years ago

pam has 3 times as many green beads as red beads and twice as many blue beads as green beads. She has 150 beads in total. How ma

lilavasa [31]

25
$150 \div 3 =$
answer

5 0

3 years ago

ad-work [718]

Answer:

Use the Pythagorean Theorem in reverse by using Subtraction:

Step-by-step explanation:

$\displaystyle a^2 + b^2 = c^2 \\ \\ -b^2 + c^2 = a^2\:OR\:-a^2 + c^2 = b^2$

I am joyous to assist you anytime.

3 0

3 years ago