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charle [14.2K]
3 years ago
13

Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. A = 56°, a = 16, b = 17 (5

points)
Mathematics
1 answer:
Blizzard [7]3 years ago
7 0

Answer:

B = 61.75°

Step-by-step explanation:

The formula for the Law of Sines is given as:

a/ sin A = b/ sin B

In the question, we are given the following values

A = 56°, a = 16, b = 17

We are to solve for B

Hence,

16/ sin 56° = 17/sin B

Cross Multiply

sin B × 16 = sin 56° × 17

sin B = sin 56° × 17/16

sin B = 0.88

B = arc sin(0.88)

B = 61.74536°

Approximately B = 61.75°

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Setler79 [48]
H = height of triangle
b = length of triangle base
A = area of triangle

Recall the formula for area of a triangle :

A = 1/2 bh

Plug in what was given in the problem :

h = b - 5
A = 42

A = 1/2 bh
42 = 1/2 b (b-5) 

6 0
3 years ago
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COMPRÉ 30 LIBROS A 40 BS CADA UNO ; VENDÍ UNOS CUANTOS A 360 BS, A 36 BS CADA UNO. ¿ EN CUANTO DEBO VENDER CADA UNO DE LOS RESTA
Ksenya-84 [330]

Answer:

28BS

Step-by-step explanation:

Compré 30 libros a 40 bs cada uno;

Precio de costo = 30 × 40BS

= 1200 BS

Vendí unos pocos a 360 Bs, a 36 Bs cada uno.

Número de libros vendidos = 360 BS / 36 BS

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Número de libros restantes = 40 BS - 10 BS

= 30 BS

¿Cuánto debo vender cada uno de los libros restantes para no perder ni ganar nada?

Para no ganar ni perder nada, la cantidad total que queda para vender los libros =

1200BS - 360 BS = 840 BS

La cantidad para vender cada uno de los libros restantes sin ganar ni perder nada se calcula como:

840BS / Número de libros restantes

= 840BS / 30BS

= 28BS

8 0
3 years ago
Help please! I cant do this
vova2212 [387]
Let's solve the inequality.

x - 5 >= -2

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x >= 3

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I got in a big fight with my mom recently, I'm really lost and Idk what to do, My parents take my phone away all the time and th
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Answer:

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3 0
3 years ago
Factor the following<br>(a²+b²)²-18(a²+b²)-88​
navik [9.2K]

Answer:

\rm\displaystyle(  {a}^{2}  +  {b}^{2} - 22)( {a}^{2}  +  {b}^{2}   +  4)

Step-by-step explanation:

we would like to factor the following:

\rm\displaystyle ( {a}^{2}  +  {b}^{2}  {)}^{2}  - 18( {a}^{2}  +  {b}^{2} ) - 88

let a²+b²=x

thus substitute:

\rm\displaystyle x {}^{2}  - 18x- 88

rewrite the middle term as 4x-22x:

\rm\displaystyle x^{2}  + 4x - 22x -  88

factor out x:

\rm\displaystyle x( x^{}  + 4)- 22x -  88

factor out -22:

\rm\displaystyle x( x^{}  + 4)- 22(x  +  4)

group:

\rm\displaystyle( x- 22)(x  +  4)

substitute back:

\rm\displaystyle(  {a}^{2}  +  {b}^{2} - 22)( {a}^{2}  +  {b}^{2}   +  4)

and we are done!

6 0
3 years ago
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