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3 years ago

Round 81.139 to the nearest tenth

2 answers:

6 0

If the number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up (+1).

If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down (no change).

81.139 ≈ 81.1

alex41 [277]3 years ago

5 0

The first place after the decimal place is the tenth's place, then next is the hundreth's and so on

when rounding, if the number is 5 or more then round up , if less than 5, round down
exg\
.5 runded up=1
.4 rounded would be 0

so 81.139
disregard the 9
81.13
3 is less than 5
81.10

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Identify the functions that are continuous on the set of real numbers and arrange them in ascending order of their limits as x t

Studentka2010 [4]

Answer:

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

Step-by-step explanation:

1. $f(x)=\frac{x^2+x-20}{x^2+4}$

The denominator of f is defined for all real values of x

Therefore, the function is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x^2+x-20}{x^2+4}=\frac{25+5-20}{25+4}=\frac{10}{29}=0.345$

3. $h(x)=\frac{3x-5}{x^2-5x+7}$

$x^2-5x+7=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function h is defined for all real values.

$\lim_{x\rightarrow 5}\frac{3x-5}{x^2-5x+7}=\frac{15-5}{25-25+7}=\frac{10}{7}=1.43$

2. $g(x)=\frac{x-17}{x^2+75}$

The denominator of g is defined for all real values of x.

Therefore, the function g is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x-17}{x^2+75}=\frac{5-17}{25+75}=\frac{-12}{100}=-0.12$

4. $i(x)=\frac{x^2-9}{x-9}$

x-9=0

x=9

The function i is not defined for x=9

Therefore, the function i is not continuous on the set of real numbers.

5. $j(x)=\frac{4x^2-7x-65}{x^2+10}$

The denominator of j is defined for all real values of x.

Therefore, the function j is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{4x^2-7x-65}{x^2+10}=\frac{100-35-65}{25+10}=0$

6. $k(x)=\frac{x+1}{x^2+x+29}$

$x^2+x+29=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function k is defined for all real values.

$\lim_{x\rightarrow 5}\frac{x+1}{x^2+x+29}=\frac{5+1}{25+5+29}=\frac{6}{59}=0.102$

7. $l(x)=\frac{5x-1}{x^2-9x+8}$

$x^2-9x+8=0$

$x^2-8x-x+8=0$

$x(x-8)-1(x-8)=0$

$(x-8)(x-1)=0$

$x=8,1$

The function is not defined for x=8 and x=1

Hence, function l is not defined for all real values.

8. $m(x)=\frac{x^2+5x-24}{x^2+11}$

The denominator of m is defined for all real values of x.

Therefore, the function m is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{x^2+5x-24}{x^2+11}=\frac{25+25-24}{25+11}=\frac{26}{36}=\frac{13}{18}=0.722$

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

6 0

3 years ago

Sally has been measuring the tree in her yard for a science project. The tree has grown 12 of an inch each month and grown a tot

hammer [34]

Answer:

Sally has been measuring the tree for 4 months

Step-by-step explanation:

The correct question is as follows;

Sally has been measuring the tree in her yard for a science project. The tree has grown 1/2 of an inch each month and grown a total of 2 inches taller. How many months has Sally been measuring this tree?

.........................................................................................

Solution;

The tree has grown 1/2 of an inch each month and has grown a total of 2 inch taller.

We now need to know the number of months in which the measuring has been taking place.

To know the number of months, we simply need to divide the change in height which is 2 inch by the individual month growth rate which is 1/2 inch

So mathematically, that would be 2/1/2 = 2 * 2 = 4 months

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2 years ago

Find the value of the following expression:

Phoenix [80]

(3^8 ⋅ 2^-5 ⋅ 9^0)^-2 ⋅ (2^ -2 / 3^3) ^4 ⋅ 3^28 =

(6561 * 0.03125 * 1)^2 * (0.00925)^4 * 22876792454961 =

42037.81348 * 0.00000000732094 * 22876792454961 =

7040477235.56798349

round answer as needed

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3 years ago

What’s the difference between a radius and a diameter

MatroZZZ [7]

Task as is half of the diameter

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2 years ago

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How would 1/5 be written as a decimal

RSB [31]

1/5 is written as .2 because .2 x 5 is 1

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3 years ago

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