Answer:
step 1
Find the average growth per year of the populations of rabbits farm A
Over the first 2 years
for t=0
numbers of rabbits=5 (is not exact)
for t=2
numbers of rabbits=40
average=[40-5]/2---------> 17.5
step 2
Find the average growth per year of the populations of rabbits farm B
Over the first 2 years
for t=0
numbers of rabbits=5 (is not exact)
for t=2
numbers of rabbits=30
average=[30-5]/2---------> 12.5
step 3
Compare the average growth per year of the populations of rabbits on both farms
farm A=17.5
farm B=12.5
the average rate of population growth of rabbits in farm A is greater than average rate of population growth of rabbits in farm B by about 5 rabbits per year.
therefore
the answer is the option C)
the average rate of population growth of rabbits in farm A is greater than average rate of population growth of rabbits in farm B by about 6 rabbits per year.
Step-by-step explanation:
4- 2/3 (4-1/6) divided by 3/4
parenthesis first
4 - 2/3 (3 5/6) divided by 3/4
change to an improper fraction (6*3+5)/6
4 - 2/3 ( 23/6)divided by 3/4
4 - 46/18 divide by3/4
copy dot flip
4 - 46/18 * 4/3
4 - 23/9 * 4/3
4 - 92/27
get a common denominator of 27
4*27/27 -92/27
108/27 - 92/27
16/27
That answer would be: 987.6666..... (6 repeating)