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TiliK225 [7]
3 years ago
11

Use the Pythagorean Theorem to find the distance between points A and E. A) 2 13 B) 117 C) 127 D)

Mathematics
2 answers:
puteri [66]3 years ago
5 0

Answer:

Square root of 117 is the correct answer

Step-by-step explanation:

NNADVOKAT [17]3 years ago
3 0
I need a picture to slove this sorry
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In quadrilateral QRST, QS = RT.IS QRST a rectangle?<br> a:no<br> b:cannot be determined <br> c:yes
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C

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If x and y are positive integers such that 5x+3y=100, what is the greatest possible value of xy? please include steps. Thank you
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The greatest possible value of xy is 165.

Step-by-step explanation:

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Jenna has 8 pairs of jeans. Three of them are blue. What percentage of her jeans is blue?
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A) blue/total = (3+2)/(8+2) = 5/10 = 50%

b) blue/total = (3)/(8 +2) = 3/10 = 30%
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3 years ago
A person traveling from Seattle to Sydney has three airlines to choose from. 40% of travelers choose airline A, and this airline
dalvyx [7]

Answer:

46.67% probability that they flew with airline B.

Step-by-step explanation:

We have these following probabilities:

A 40% probability that a traveler chooses airline A.

A 35% probability that a traveled chooses airline B.

A 25% probability that a traveler chooses airline C.

If a passenger chooses airline A, a 10% probability that he arrives late.

If a passenger chooses airline B, a 15% probability that he arrives late.

If a passenger chooses airline C, a 8% probability that he arrives late.

If a randomly selected traveler is on a flight from Seattle which arrives late to Sydney, what is the probability that they flew with airline B?

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

So

What is the probability that the traveler flew with airline B, given that he was late?

P(B) is the probability that he flew with airline B.

So P(B) = 0.35

P(A/B) is the probability of being late when traveling with airline B. So P(A/B) = 0.15.

P(A) is the probability of being late. This is the sum of 10% of 40%(airline A), 15% of 35%(airline B) and 8% of 25%(airline C).

So

P(A) = 0.1*0.4 + 0.15*0.35 + 0.08*0.25 = 0.1125

Probability

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.35*0.15}{0.1125} = 0.4667

46.67% probability that they flew with airline B.

5 0
3 years ago
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