Given:
The perimeter of a rhombus of side d cm is

To find:
The perimeter of a rhombus of side 3.2 cm.
Find the length of a side of a rhombus of perimeter 14 cm.
Solution:
Side of a rhombus is 3.2 cm. So, its perimeter is


Therefore, the perimeter of a rhombus of side 3.2 cm is 12.8 cm.
The perimeter of another rhombus is 14 cm, and we need find its side.


Divide both sides by 4.


Therefore, the length of a side of a rhombus of perimeter 14 cm is 3.5 cm.
Answer:
Perimeter is 17.07
Step-by-step explanation:
We know that DF = EF = 5 cm, since D and E are the midpoints of AC and AB, both of which are 10 cm in length.
We need to use the Pythagorean theorem to get the length of DE.

So the perimeter of DEF is 5 + 5 + 7.07 = 17.07
In this exact order:
5+1.75x=y
Sorry for the wait..Hope this helps