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GalinKa [24]
3 years ago
12

What is 2 hundreds+ 2 tens + 18 ones

Mathematics
1 answer:
3241004551 [841]3 years ago
5 0

When you add them together you get 238.

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19=a+5<br> please answer fast!!!!
dexar [7]

Answer:15

Step-by-step explanation:

8 0
3 years ago
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Solve for k. Describe the steps taken to find the solution.<br> 8 + 10 - 6k = 6(4 - k)
BartSMP [9]

Answer:

no solutions

Step-by-step explanation:

8 + 10 - 6k = 6(4 - k)

Distribute

8 + 10 - 6k = 24 -6k

Combine like terms

18 -6k = 24 -6k

Add 6k  to each side

18 - 6k +6k = 24 - 6k+6k

18 = 24

This is never true so there are no solutions

5 0
3 years ago
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an anchor line for a tower needs to be replaced. the tower is 96ft tall. the anchor line is 105ft long. how far from the tower c
Fynjy0 [20]

Answer:

Let x be how far from the tower can it be placed

by Pythagorus theorem

x^2  + 96^2   = 105^2

x=√(105^2  -96^2 )=√1809 = 42.532340 = 42.5 ft


3 0
3 years ago
Find the dimensions of a rectangle (in m) with area 1,000 m2 whose perimeter is as small as possible. (Enter the dimensions as a
Amanda [17]

The perimeter of the rectangle is the sum of its dimensions

The dimensions that minimize the perimeter are \mathbf{10\sqrt{10 },10\sqrt{10 }}

The area is given as:

\mathbf{A = 1000}

Let the dimension be x and y.

So, we have:

\mathbf{A = xy = 1000}

Make x the subject

\mathbf{x = \frac{1000}{y}}

The perimeter is calculated as:

\mathbf{P = 2(x + y)}

Substitute \mathbf{x = \frac{1000}{y}}

\mathbf{P = 2(\frac{1000}{y} + y)}

Expand

\mathbf{P = \frac{2000}{y} + 2y}

Differentiate

\mathbf{P' = -\frac{2000}{y^2} + 2}

Set to 0

\mathbf{ -\frac{2000}{y^2} + 2 = 0}

Rewrite as:

\mathbf{ -\frac{2000}{y^2}  = -2}

Divide both sides by -1

\mathbf{\frac{2000}{y^2}  = 2}

Multiply y^2

\mathbf{2000  = 2y^2}

Divide by 2

\mathbf{1000  = y^2}

Take square roots of both sides

\mathbf{y = \sqrt{1000 }}

\mathbf{y = 10\sqrt{10 }}

Substitute \mathbf{y = \sqrt{1000 }} in \mathbf{x = \frac{1000}{y}}

\mathbf{x = \frac{1000}{\sqrt{1000}}}

\mathbf{x = \sqrt{1000}}

\mathbf{x = 10\sqrt{10 }}

Hence, the dimensions that minimize the perimeter are \mathbf{10\sqrt{10 },10\sqrt{10 }}

Read more about perimeters at:

brainly.com/question/6465134

8 0
3 years ago
If r= 1 and 0=3.14/4, what is the approximate arc length?
baherus [9]

The approximate arc length from the task content is; Choice C; 0.785 units.

<h3>What is the approximate arc length?</h3>

Since the arc length is given mathematically by the formular;

Arc length = (A/360) × 2πr

Hence, since A = π/4 = 18/4 = 45.

Hence; Arc Length = (45/360) × 2 × 3.14 ×1

Arc length = 6.28/8 = 0.785 units.

Read more on arc length;

brainly.com/question/2005046

#SPJ1

6 0
2 years ago
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