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oksano4ka [1.4K]
3 years ago
13

Z = 8 + 6x -px for x

Mathematics
1 answer:
NeTakaya3 years ago
7 0

Answer:

x=\frac{z-8}{-p+6}

Step-by-step explanation:

Flip the equation.

−px+6x+8=z

Add -8 to both sides.

−px+6x+8+−8=z+−8

−px+6x=z−8

Factor out variable x.

x(−p+6)=z−8

Divide both sides by -p+6.

\frac{x(-p+6)}{-p+6} =\frac{z-8}{-p+6}

x=\frac{z-8}{-p+6}

hope this helps

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URGENT: I need these problems answered and steps :/ Will give the first person BRAINLIEST and please show the steps and please p
hjlf

Answer:

1) -15/32

2) 2/15

3) -203.5

4) -3/2 = -1.5

5) 10/3 = 3 1/3

Step-by-step explanation:

For 1, you just multiply the numerators and denominators together (3 by 5, 4 by 8) and then because it is negative, add the negative sign.

For 2, you multiply again, but because there are 2 negative signs, it becomes positive.

For 3, you divide 81.4 by 0.4, you could also divide 814 by 4.

For 4, you keep change flip, so the equation would become -9/4 (-2 1/4=-9/4) and 3/2 would become 2/3. The equation would be (-9/4 * 2/3). Then, you would get -18/12 which is -3/2.

For 5, you just multiply 4/3 by 5/2 which is 20/6 and because 2 negatives, it becomes positive.

3 0
3 years ago
Read 2 more answers
A) Use the definition of Laplace transform to find L{f }. (Do the integrals.) For what values of s is L{f } defined?f(t) = (2t+1
kiruha [24]

For the given function f(t) = (2t + 1) using definition of Laplace transform the required solution is L(f(t))s = [ ( 2/s²) + ( 1/s) ].

As given in the question,

Given function is equal to :

f(t) = 2t + 1

Simplify the given function using definition of Laplace transform we have,

L(f(t))s = \int\limits^\infty_0 {f(t)e^{-st} } \, dt

          =  \int\limits^\infty_0[2t +1] e^{-st} dt

          = 2\int\limits^\infty_0 te^{-st} + \int\limits^\infty_0e^{-st} dt

         = 2 L(t) + L(1)

L(1) = \int\limits^\infty_0e^{-st} dt

     = (-1/s) ( 0 -1 )

     = 1/s , ( s >  0)

2L ( t ) = 2\int\limits^\infty_0 te^{-st}

        =  2[t\int\limits^\infty_0 e^{-st} - \int\limits^\infty_0 ({(d/dt)(t) \int\limits^\infty_0e^{-st} \, dt )dt]

        =  2/ s²

Now ,

L(f(t))s = 2 L(t) + L(1)

          = 2/ s² + 1/s

Therefore, the solution of the given function using Laplace transform the required solution is L(f(t))s = [ ( 2/s²) + ( 1/s) ].

Learn more about Laplace transform here

brainly.com/question/14487937

#SPJ4

8 0
1 year ago
Solve using substitution <br> x-10y=10<br> x= -10
34kurt
-10 -10y = 10
+10 +10

-10y = 20

20/-10 = -2

Y = -2
4 0
2 years ago
Read 2 more answers
Find the value of n<br><br> 6/n = 5/120
sleet_krkn [62]

Answer:

n = 144

Step-by-step explanation:

          6 / n = 5/120

         6 * 120 = 5*n

               5n = 6*120

               5n = 720

                 n = 720/5

                 n = 144

8 0
3 years ago
Read 2 more answers
If a auditorium has 850 seats tickets were sold for 816 of the seats of the seats for what percent of the seats were tickets sol
Sonja [21]
It's 96%


816/850 = 0.96, which is 96%

Hope I helped! ( Smiles )
8 0
3 years ago
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