Multiple: 4 * 1
/2 = 4 · 1 = 4
/2 = 2 · 2
1 · 2 1 · 2 = 2
Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(4, 2) = 2
Multiple: 7 * 2 = 14
Multiple: 5 * 1
/3 = 5 · 1
1 · 3 = 5
/3
Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(5, 3) = 1
Multiple: 3 * 5
/3 = 3 · 5
1 · 3 = 15
/3 = 5 · 3
1 · 3 = 5
Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(15, 3) = 3
Add: 14 + 5 = 19
Multiple: -3 * 1
/2 = -3 · 1
1 · 2 = -3
/2
= -1.5 · 2
1 · 2
Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(-3, 2) = 2
Multiple: 1/2 * (-3
/2
) = 2 · (-3)
1 · 2 = -6
/2 = -3 · 2
1 · 2 = -3
Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(-6, 2) = 2
Add: 19 + (-3) = 16
7(4×1/2) + 3(5×1/3) + 2(-3×1/2) = 16
/1 = 16
Work shown above! in the end she is 2 blocks north of her apartment. hope this helps c:
Answer:
x = 5.7 years after 2000
Step-by-step explanation:
So the year when both the amount of users were the same can be found by using the both equations to solve for x (since y is the same)
48x + y = 729
we will take the value of y from this equation and use it in the other equation
y = 729 - 48x
135x - 2y = -140
135x - 2(729 - 48x) = -140
135x -1458 + 98x = -140
231x = 1318
x = 1318/231
x = 5.7 years after 2000
The answer is B, 50 miles!
