<u>Given</u>:
Given that the two sides of the triangle are x, 4.0 and 5.6
We need to determine the range of possible sizes for the side x.
<u>Range of x:</u>
The range of x can be determined using the triangle inequality theorem.
The triangle inequality theorem states that, "if any side of a triangle must be shorter than the other two sides added together".
Thus, applying the theorem, we have;


Also, the the triangle inequality theorem states that, "the third side must be also larger than the difference between the other two sides".
Thus, we have;


Thus, the range of possible values for x are 
x = 109
this is pentagon
the sum of the interior angles of a polygon is
sum = 180°( n - 2) where n is the number of sides.
sum = 180° × 3 = 540° thus
x + 121+ 108 + 102 + 100 = 540
x + 431 = 540
subtract 431 from both sides
x = 540 - 431 = 109
Answer:
Ok ill try to answer
Step-by-step explanation:
Answer:
It’s D because no lines overlap so it passes the vertical line test
Step-by-step explanation:
Answer:
->a is 2
->b is one eight
Step-by-step explanation:
one fourth dividen in two becomes one eight.