Answer:
bhjjjjjnm bvgcvjk
Step-by-step explanation:
Answer:
100
Step-by-step explanation:
We have the sum of first n terms of an AP,
Sn = n/2 [2a+(n−1)d]
Given,
36= 6/2 [2a+(6−1)d]
12=2a+5d ---------(1)
256= 16/2 [2a+(16−1)d]
32=2a+15d ---------(2)
Subtracting, (1) from (2)
32−12=2a+15d−(2a+5d)
20=10d ⟹d=2
Substituting for d in (1),
12=2a+5(2)=2(a+5)
6=a+5 ⟹a=1
∴ The sum of first 10 terms of an AP,
S10 = 10/2 [2(1)+(10−1)2]
S10 =5[2+18]
S10 =100
This is the sum of the first 10 terms.
Hope it will help.
Answer:
m = 4
you can find the answer for this on m a t h w a y (without the spaces)
I hope this helps!
The range is 30 to find the range u subtract the biggest from the smallest so 81-51=30 hope this helps
Answer:
m is the right answer
Step-by-step explanation:
no step hope yu mark me as brainliest
