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hjlf
3 years ago
12

The area of the smaller square

Mathematics
1 answer:
Pani-rosa [81]3 years ago
6 0
Hmm, so that means that the diagonal of the square is 8

we draw and get a right triangle

pythagorean theorem
the legs are the same measure since it's a square
the hyptonue is 8
so
remember if the legs are a and b and the hypotnuse is c then
a²+b²=c²

alrighty
a=b
c=8

a²+a²=8²
2a²=64
divide both sides by 2
a²=32
sqrt both sides
a=√32

wait, the area is side times side, but it's a square so it's side² which is a²=32

the area is 32

answer is A
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If the average (arithmetic mean) of five distinct positive integers is 10, what is the difference between the largest possible v
Arte-miy333 [17]

Answer:

The difference between the largest possible value of the greatest integer and the least possible value of the greatest of the five integers = 4

Step-by-step explanation:

<u>Step 1</u>:-

let 'x' be the number

The sequence of arithmetic progression of distinct positive integers

x , x+1 , x+2 , x+3 , x+4

Given the average of five distinct positive integers is 10

\frac{x+x+1+x+2+x+3+x+4}{5} = 10

on simplification , and cross multiplication , we get

5x +10 = 5 X10

5x +10 =50

subtracting'10' on both sides, we get

5x +10 - 10 = 50 -10

5x =40

dividing '5' on both sides, we get

x = 8

The number is '8'

Step 2:-

Now the arithmetic sequence of five numbers are

x , x+1 , x+2 , x+3 , x+4

8 , 9, 10 , 11 , 12

In this sequence is smallest number is '8' and

The largest number is '12'

the difference between the largest possible value of the greatest integer and the least possible value of the greatest of the five integers

= largest possible value - least possible value

= 12 - 8 =4

<u>Final answer</u> = 4

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Step-by-step explanation: Use exact numbers.

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