According to the fundamental theorem of algebra, how many zeros does the function f(x) = 4x3 − x2 − 2x + 1 have?
2 answers:
Answer:
3 zeros
Step-by-step explanation:
The fundamental theorem of algebra states that any polynomial with degree m>0 and complex coefficients has at least one complex root.
Corollary of fundamental theorem states that for any polynomial with degree m>0 has exactly m solutions.
The given function is 4x^3-x^2-2x+1
Because it is a polynomial function with degree 3>0 , Therefore by corollary of fundamental theorem of algebra , it has 3 zeroes.
Answer:
Step-by-step explanation:
4x3 − x2 − 2x + 1
I show one zero. X= - 0.78769256
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Answer:
The answer is b=128
Step-by-step explanation:
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180-52=128
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A-b = 43----(1) a+b = 13----(2) (1)+(2) 2a=56 then a=56/2= 28 so b=13-28= -15 so that the numbers are -15 and 28