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3 years ago

15.09 ÷ 0.01 = ? 267.4 ÷ 1/10 = ?

Mathematics

2 answers:

Masja [62]3 years ago

8 0

Answer:

Dividing by a fraction is multiplying by the reciprocal

15.09/1/100=15.09*100=1509

267.4/1/10=267.4*10=2674

eduard3 years ago

7 0

Answer:

15.09 ÷ 0.01 = 1509

267.4 ÷ 1/10 = 2674

hope these are the answers you are looking for

Step-by-step explanation:

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Please help me I don’t understand this

miss Akunina [59]

Answer:

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3 years ago

In the coordinate plane, what is the length of the line segment that connects points at (5,4) and (-3,-1)

baherus [9]

Answer:

9.434 units

Step-by-step explanation:

Given data

points (5,4) and (-3,-1)

x1= 5

y1= 4

x2= -3

y2= -1

The expression for the distance between two points is

d=√((x_2-x_1)²+(y_2-y_1)²)

substitute

d=√((-3-5)²+(-1-4)²)

d=√((-8)²+(-5)²)

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d=√89

d=9.4339

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8 0

3 years ago

Let represent the number of tires with low air pressure on a randomly chosen car. The probability distribution of is as follows.

Sindrei [870]

Answer:

a) $P(X=3) = 0.1$

b) $P(X\geq 3) =1-P(X$

And replacing we got:

$P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4$

c) $P(X=4) = 0.3$

d) $P(X=0) = 0.2$

e) $E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2$

f) $E(X^2)= \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4$

And the variance would be:

$Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4$

And the deviation:

$\sigma =\sqrt{2.4} = 1.549$

Step-by-step explanation:

We have the following distribution

x 0 1 2 3 4

P(x) 0.2 0.3 0.1 0.1 0.3

Part a

For this case:

$P(X=3) = 0.1$

Part b

We want this probability:

$P(X\geq 3) =1-P(X$

And replacing we got:

$P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4$

Part c

For this case we want this probability:

$P(X=4) = 0.3$

Part d

$P(X=0) = 0.2$

Part e

We can find the mean with this formula:

$E(X)= \sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2$

Part f

We can find the second moment with this formula

$E(X^2)= \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4$

And the variance would be:

$Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4$

And the deviation:

$\sigma =\sqrt{2.4} = 1.549$

4 0

3 years ago

What is the area of a circle that has a diameter of 16in

rjkz [21]

Answer:

A=πr2

A=π8^2

A=π* 8* 8

A= 64π

A= 64x3.14

A= 200.96 in^2

Step-by-step explanation:

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3 years ago

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3 years ago

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