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yaroslaw [1]
3 years ago
10

A central angle in this diagram is:

Mathematics
1 answer:
Mrrafil [7]3 years ago
3 0

√HOL

√HOL

√HOL

√HOL

√HOL

√HOL

√HOL√HOL√HOL√HOL√HOL√HOL√HOL√HOL√HOL√HOL√HOL√HOL√HOL√HOL√HOL√HOL√HOL√HOL√HOL√HOL√HOL√HOL√HOL√HOL√HOL√HOL√HOL

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Two lines intersecting at a right angle
Zinaida [17]

Answer:

Perpendicular Lines

5 0
3 years ago
Fiona recorded the mean math exam grade for six random samples of students from the entire seventh-grade class. Sample Sample Me
Charra [1.4K]

The reason why Fiona cannot make a valid prediction based on the mean of the population is that the variation of Fiona’s samples is too large.

<h3>Why can't Fiona use the means she recorded?</h3><h3 />

Mean is quite sensitive to outliers so it is best used when the variation between variables is not too much.

In Fiona's case, there variation is quite high with high variable of 95 compared to a low value of 45.

Find out more on effect of outliers at brainly.com/question/16815987.

#SPJ1

7 0
2 years ago
So if you have y=1/4x-1 and y= 1/4x+5 what are x and y
kramer
The Answer is
X= -1
Y= -5/4
7 0
3 years ago
Simplyfy 5 x a x 5 x a
prohojiy [21]

Step-by-step explanation:

5×a×5×a

collect like terms

5×5×a×a

25×a^2

25a^2

8 0
2 years ago
Write the standard form of the line that passes through (-1,-3) and (2,1).
kobusy [5.1K]

Answer:

Step-by-step explanation:

\mathrm{Line\:passing\:through\:}\left(-1,\:-3\right)\mathrm{,\:}\left(2,\:1\right)\\\\\mathrm{Find\:the\:line\:}\\\mathbf{y=mx+b}\mathrm{\:passing\:through\:}\left(-1,\:-3\right)\mathrm{,\:}\left(2,\:1\right)\\\\\mathrm{Compute\:the\:slope\:}\left(-1,\:-3\right),\:\left(2,\:1\right):\quad \\m=\frac{4}{3}\\\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\\\\\left(x_1,\:y_1\right)=\left(-1,\:-3\right),\:\left(x_2,\:y_2\right)\\\left\\

\\m=\frac{1-\left(-3\right)}{2-\left(-1\right)}\\\\Refine\\\\m=\frac{4}{3}\\\\\mathrm{Compute\:the\:}y\mathrm{\:intercept}:\quad b=-\frac{5}{3}\\\\y=\frac{4}{3}x-\frac{5}{3}\\

Convert equation to standard form

y - \frac{4}{3} x + \frac{5}{3} = 0\\\\Multiply \:through\: by\: 3;\\\\3\times (y - \frac{4}{3} x + \frac{5}{3} )=0\\\\3y -4x+5 = 0\\Arrange\:n\:form\:of \:;\\Ax +By = C\\\\-4x +3y =-5

5 0
3 years ago
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