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Naily [24]
2 years ago
13

Noah needs to order some new supplies for the restaurant where he works. The restaurant needs at least 503 knives. There are cur

rently 391 knives. If each set on sale contains 10 knives, which inequality can be used to determine xx, the minimum number of sets of knives Noah should buy?
Mathematics
1 answer:
anastassius [24]2 years ago
4 0

Answer:

10x+391≥503

Step-by-step explanation:

let x = # of sets

If you need at least 503 knives, both the sets of knives and the initial amount we already have (391) must add to have a number of knives greater than or equal to the minimum required amount.

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Inessa [10]

Answer:

-4x-1

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Thank you guys fir the help
KiRa [710]

9514 1404 393

Answer:

  A

Step-by-step explanation:

The function f(x) is required in the numerator, eliminating choices C and D.

The restriction is that function g cannot be zero, so we cannot have ...

  3x +2 = 0

  3x = -2

  x = -2/3 . . . . . eliminates choice B; confirms choice A

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2 years ago
Help me with my math ASAP!!!!
almond37 [142]

Answer:

f = 78

g = 3.5

Step-by-step explanation:

First we need to find f.

We can use the equation 72 + (f + 30) = 180 to solve for f.

We can then change that equation to 72 + f + 30 = 180, since the Commutative Property of Addition says that you can have any addition in any order.

Now, we can solve the equation.

102 + f = 180\\(102 - 102) + f = 180 - 102\\f = 78

Now that we solved f, we can now solve for g.

Since 25 equals 8g -3, we can solve the equation 8g - 3 = 25.

Here is how you solve it:

8g - 3 = 25\\8g + (-3 + 3) = 25 + 3\\8g = 28\\g = \frac{28}{8}

Since \frac{28}{8} equals 3.5, which is the simplest form, that is the answer.

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3 0
3 years ago
What is x2 – 6 = 16x + 30 rewritten in standard form, then factored?
AlexFokin [52]

Answer:

The standard form of quadratic equation is x^2-16x-36=0

The factored form of x^2-16x-36=0 is (x+2)(x-18)=0

Step-by-step explanation:

Given equation x^2-6=16x+30

We have to write  in standard form and then factorize the given equation.

The standard form for a general quadratic equation is given as ax^2+bx+c=0

Consider x^2-6=16x+30

Taking all terms to left side, we have,

x^2-6-16x-30=0

Adding like terms, we have,

x^2-16x-36=0

Now we will factorize it.

We will solve the quadratic equation x^2-16x-36=0 using middle term splitting method,

-16x can be written as -18x+2x

x^2-16x-36=0  becomes

\Rightarrow x^2-18x+2x-36=0

Taking x common from first two terms  and 2 common from last two terms we have,

\Rightarrow x(x-18)+2(x-18)=0

\Rightarrow (x+2)(x-18)=0

Thus, the factored form of x^2-16x-36=0 is (x+2)(x-18)=0

4 0
2 years ago
Read 2 more answers
2k^2-5k-18=0 what is both of the values of k? plz help!!! 15 pts!!!
ddd [48]
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.

jk=ac and j+k=b

The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...

2k^2-5k-18=0

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(2k-9)(k+2)=0

so k=-2 and 9/2

k=(-2, 4.5)
5 0
3 years ago
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