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Diano4ka-milaya [45]
2 years ago
6

A man drove his car at 80km per hr for 1 and a quarter hrs .He rested for 45mins and then covered 240km, at the same time. Calcu

late his average speed for the whole journey​
Mathematics
1 answer:
prisoha [69]2 years ago
3 0

Answer:

Probably 128 km/h, but maybe 98.5 km/h. See below.

Step-by-step explanation:

What does "at the same time" mean?

If it means that he covered the 240 km in the same time as he convered the 80 km, then this is how you solve it:

80 km in 1.25 hour

240 km in 1.25 hour

Total distance: 80 km + 240 km = 320 km

Total time: 1.25 hour + 1.25 hour = 2.5 hour

average speed = (total distance)/(total time) = 320 km / 2.5 hour = 128 km/h

If it means he covered the 240 km in the same time he covered the 80 km plus the rest, then this is how you solve it:

80 km in 1.25 hour

240 km in 1.25 hour + 45 min = 240 km in 1.25 houir + 0.75 hour = 240 km in 2 hour

Total distance: 80 km + 240 km = 320 km

Total time: 1.25 hour + 2 hour = 3.25 hour

average speed = (total distance)/(total time) = 320 km / 3.25 hour = 98.5 km/h

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Answer:

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length of arc S = 15π

Attached is the image of the arc.

Step-by-step explanation:

Given;

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3 years ago
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Kevin installed a certain brand of automatic garage door opener that utilizes a transmitter control with four independent​ switc
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Kevin installed a certain brand of automatic garage door opener that utilizes a transmitter control with four independent​ switches, each one set on or off. The receiver​ (wired to the​ door) must be set with the same pattern as the transmitter. If six neighbors with the same type of opener set their switches​ independently.<u>The probability of at least one pair of neighbors using the same​ settings is 0.65633</u>

Step-by-step explanation:

<u>Step 1</u>

In the question it is given that

Automatic garage door opener utilizes a transmitter control with four independent​ switches

<u>So .the number of Combinations possible with the Transmitters </u>=

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<u> Step 2</u>

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<u> Step 3</u>

Probability of at least one pair of neighbors using the same settings=

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<u> Step 4</u>

<u>So the probability of at least </u>one pair of neighbors using the same settings

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3 years ago
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