Question

Which problem can best be solved with the inequality 40 – 3x ≥ 5?

Answer 1

A. You bring $40 to the carnival. You need to keep at least $5 for the bus ride home. how many $3 dollar rides can you go on

Answer 2

Answer:

The problem "You bring $40 to the carnival. You need to keep at least $5 for the bus ride home. How many $3 rides can you go on?" can be solved using the given inequality.

Solution:

The given inequality is $40-3 x \geq 5$

For the best solution of the inequality, we need to subtract 40 from both the side of the equation for getting the value of x.  

Now subtracting 40 from both side we get,

$40-3 x-40 \geq 5-40$

$\Rightarrow-3 x \geq 5-40$

$\Rightarrow-3 x \geq-35$

$\Rightarrow x=\frac{35}{3}$

Now if we put the value of x in the equation, we get,  

$\Rightarrow 40-3 \times\left(\frac{35}{3}\right) \geq 5$

$\Rightarrow 40-35 \geq 5$

$\Rightarrow 5>=5$

The value of $x=\frac{35}{3}=11\left(\frac{2}{3}\right)$

The answer for the problem will be maximum of 11 rides can be taken.