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docker41 [41]
4 years ago
12

Solve for x Urgent need help

Mathematics
1 answer:
fiasKO [112]4 years ago
6 0
I believe you need to solve this using the quadratic formula!
To begin, this is what it is:
x= -b ± <span>√ b^2 - 4ac / 2a
Just plug in what you have in your problem...
2 being a, 13 being b, and -24 being c.
So we get:
x= -13 </span>± <span>√13^2 - 4(2)(-24) / 2(2)
x= -13 </span><span>± √169 - 8 (-24) / 4</span>
<span>x= -13 <span>± √169 + 192 / 4</span>
x= -13 </span>± √<span>361 / 4
The square root of 361 is 19.
So you have: -13 </span><span>± 19 / 4.
Here's where you take the equation </span>-13 <span>± 19 and put the addition and subtraction sign to use.
-13 - 19 = -32
and
-13 + 19 = 6
Now all is left to do is divide the two numbers by 4.
-32/4 = -8
and
6/4 = 3/2

x = -8, 3/2</span>
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The value of \csc \theta is \frac{5}{4}

Explanation:

Given that the function cos \ \theta is cos \ \theta= \frac{3}{5}

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The formula for cos \ \theta is given by

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The value of opposite side can be determined using the formula,

opp=\sqrt{hyp^2-adj^2

opp=\sqrt{5^2-3^2}

opp=\sqrt{25-9}

opp=\sqrt{16}=4

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The formula for sin \ \theta is given by

sin \ \theta= \frac{opp}{hyp}

Substituting the values, we have,

sin \ \theta= \frac{4}{5}

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The formula for \csc \theta is given by

csc \ \theta=\frac{1}{sin \ \theta}

Substituting the values, we have,

csc \ \theta=\frac{1}{\frac{4}{5}}

csc\ \theta= \frac{5}{4}

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