Step-by-step explanation:
Follow PEMDAS
P: Parentheses
E : Exponents
M: Multiplication
D: Division
A: Addition
S: Subtraction
Question 2
Answer:
2.4 hr. = time working together
Step-by-step explanation:
Let x = time working together
x/6 = work done by Martin
x/4 = work done by Victor
Martin's part + Victor's part = 1 jog done
x/6 + x/4 = 1 Multiply thru by 12
2x + 3x = 12
5x = 12
x = 2.4 hr.
let's bear in mind that sin(θ) in this case is positive, that happens only in the I and II Quadrants, where the cosine/adjacent are positive and negative respectively.
![\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{6}}\qquad \impliedby \textit{let's find the \underline{adjacent side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{6^2-5^2}=a\implies \pm\sqrt{36-25}\implies \pm \sqrt{11}=a \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20sin%28%5Ctheta%20%29%3D%5Ccfrac%7B%5Cstackrel%7Bopposite%7D%7B5%7D%7D%7B%5Cstackrel%7Bhypotenuse%7D%7B6%7D%7D%5Cqquad%20%5Cimpliedby%20%5Ctextit%7Blet%27s%20find%20the%20%5Cunderline%7Badjacent%20side%7D%7D%20%5C%5C%5C%5C%5C%5C%20%5Ctextit%7Busing%20the%20pythagorean%20theorem%7D%20%5C%5C%5C%5C%20c%5E2%3Da%5E2%2Bb%5E2%5Cimplies%20%5Cpm%5Csqrt%7Bc%5E2-b%5E2%7D%3Da%20%5Cqquad%20%5Cbegin%7Bcases%7D%20c%3Dhypotenuse%5C%5C%20a%3Dadjacent%5C%5C%20b%3Dopposite%5C%5C%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20%5Cpm%5Csqrt%7B6%5E2-5%5E2%7D%3Da%5Cimplies%20%5Cpm%5Csqrt%7B36-25%7D%5Cimplies%20%5Cpm%20%5Csqrt%7B11%7D%3Da%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
Answer:
68
Step-by-step explanation:
97.65 is roughly 100
68℅ of 100 is 68
so it's 68
Answer:
Option 4
The answer is 10.8
Step-by-step explanation:
5/6 = 9/c
5c = 9 × 6
5c = 54
5c/5 = 54/5
c = 10.8
Thus, The value of c is 10.8
<h3>
<u>For </u><u>Verification</u>;</h3>
5/6 = 9/c
5/6 = 9/10.8
0.833 = 0.833
Hence, L.H.S = R.H.S
<u>-TheUnknownScientist</u><u> 72</u>
