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Xelga [282]
3 years ago
11

Brianna's teacher asks her which of these three expressions are equivalent to each other.

Mathematics
2 answers:
Tema [17]3 years ago
7 0

Answer:

<em>Briana's thinking is incorrect because the numbers are different when you substitute x with numbers other than 0.</em>

the two equations that are equivalent to each other are,

<u><em>5x+x−4 and 9x-3x-4</em></u>

Step-by-step explanation:

Expression A: 9x−3x−4

​Expression B: 12x−4

​Expression C: 5x+x−4

First I will substitute x for each of the equations.

9x-3x-4

when x equals: , then y equals:

1                        =        9(1)-3(1)-4= 2

2                       =         9(2)-3(2)-4=8

3                       =      9(3)-3(3)-4= 14

Now for 12x-4

when x equals: , then y equals:

1                        =        12(1)-4=  8

2                    =         12(2)-4= 20

3                       =      12(3)-4=  32

And for the final equation:

5x+x−4

when x equals: , then y equals:

1                        =        5(1)+(1)−4= 2

2                       =         5(2)+(2)−4 = 8

3                       =      5(3)+(3)−4=14

Based on this you can now see that the two equations that are equal are:

<u><em>5x+x−4 and 9x-3x-4</em></u>

<em>~CaityConcerto</em>

AnnZ [28]3 years ago
5 0

Answer:

Expressions A and C are equivalent.

Step-by-step explanation:

Expression A: 9x−3x−4   Combine like terms    6x -4

​Expression B: 12x−4   There are no terms to combine  12x-4

​Expression C: 5x+x−4  Combine like terms   6x -4

Brianna only looked at one particular value for x.  She must look at all values for x.

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Nat2105 [25]

Answer:

We conclude that the mean IQ of her students is different from the national average.

Step-by-step explanation:

We are given that the national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15.

The dean of a college want to test whether the mean IQ of her students is different from the national average. For this, she administers IQ tests to her 144 students and calculates a mean score of 113

Let, Null Hypothesis, H_0 : \mu = 100 {means that the mean IQ of her students is same as of national average}

Alternate Hypothesis, H_1 : \mu\neq 100  {means that the mean IQ of her students is different from the national average}

(a) The test statistics that will be used here is One sample z-test statistics;

               T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ N(0,1)

where, Xbar = sample mean score = 113

              s = population standard deviation = 15

             n = sample of students = 144

So, test statistics = \frac{113-100}{\frac{15}{\sqrt{144} } }

                             = 10.4

Now, at 0.05 significance level, the z table gives critical value of 1.96. Since our test statistics is more than the critical value of z which means our test statistics will fall in the rejection region and we have sufficient evidence to reject our null hypothesis.

Therefore, we conclude that the mean IQ of her students is different from the national average.

3 0
4 years ago
QUICK!!!
Svetlanka [38]

Answer:

Option B is the right choice.

Step-by-step explanation:

Given:

An are CE and an inscribed angle CBE.

Measure of inscribed angle CBE = 25 °

We have to find the measure of the arc CE.

Concept:

  • An inscribed angle is an angle with its vertex on the circle.
  • The measure of an inscribed angle is half the measure the intercepted arc.
  • Measure of inscribed angle = 1/2 × measure of intercepted arc .

To find the measure of arc CE.

⇒ \angle CBE = \frac{1}{2} \times m\ (arc\ CE)

⇒ 2\times \angle CBE = m\ (arc\ CE)

⇒ 2\times 25 = m\ (arc\ CE)

⇒ 50 = m\ (arc\ CE)

Measure of intercepted arc CE = 50 degrees.

The measure of arc CE = 50° so, option B is the right choice.

4 0
3 years ago
How do u solve these questions I have no clue
irina1246 [14]
Convert the larger unit into the smaller unit, and then solve.
4 0
3 years ago
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Do the political leanings of a network affect the news they report? During the the 2018-2019 Government shutdown, a left-leaning
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Answer:

504

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= 1008000/2000

= 504 registered voters

6 0
3 years ago
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