(x^2) - 16 / x+4 = (x-4)(x+4) / (x+4) = x-4, x not equal to -4
D is the answer.
Subtract 32 to both sides to the equation becomes -5x^2 + 7x + 9 = 0.
To solve this equation, we can use the quadratic formula. The quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [ -b ± √(b^2 - 4ac) ] / (2a)
x = [ -7 ± √(7^2 - 4(-5)(9)) ] / ( 2(-5) )
x = [ -7 ± √(49 - (-180) ) ] / ( -10 )
x = [ -7 ± √(229) ] / ( -10)
x = [ -7 ± sqrt(229) ] / ( -10 )
x = 7/10 ± -sqrt(229)/10
The answers are 7/10 + sqrt(229)/10 and 7/10 - sqrt(229)/10.
If the drawing of your octagon (or whatever) has been separated into triangles, and one triangle's area<span> is labeled, then you do not need to know the apothem. Just take the </span>area<span> of that one triangle, and multiply by the number of sides in the original </span>polygon<span>.</span>
$11=2 hrs
2hrs=$11
+2(4hrs)=$22
+2(6hrs)=$33 hrs
so 6 hrs or 7 hours and some
minutes left
H= .6.5
V=<span>πr^2h
h= v/</span>πr^2 = 2940.5/<span>π*12^2 = 6.49993 = 6.5</span>
