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Sergeeva-Olga [200]
3 years ago
10

What intermolecular forces can exist in a gaseous sample of HCl? (Select all that apply.) A)dipole-dipole B)hydrogen bonding C)i

on-dipole D)ion-induced dipole E)London dispersion
Chemistry
2 answers:
mafiozo [28]3 years ago
6 0

Answer:

Option A) and B)

Explanation:

In the HCl molecule there is no uniform distribution of charge, since the bond electrons, due to the difference in electronegativities between the two atoms, are unevenly distributed. Therefore, the HCl molecule is electrically asymmetric or polar,  so dipole-dipole forces act

Hydrogen bonds also act because it meets the condition of having hydrogen in its composition and an electronegative atom.

Nina [5.8K]3 years ago
4 0
B is the answer for this
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4 years ago
Read 2 more answers
15.89 percent carbon, 21.18 percent oxygen, and 62.93 percent osmium. what is the empirical formula
otez555 [7]

Answer:

OsCO or COOs

Explanation:

Data given

Carbon = 15.89 %

Oxygen = 21.18 %

Osmium = 62.93%

Empirical formula = ?

Solution:

First find the masses of each component

Consider total compound is 100g

As we now

mass of element = % of component

So,

15.89 g of C     = 15.89 % Carbon

21.18 g of O      =   21.18 % Oxygen

62.93 g of Os  =   62.93% Osmium

Now convert the masses to moles

For Carbon

Molar mass of C = 12 g/mol

                  no. of mole = mass in g / molar mass

Put value in above formula

                  no. of mole =  15.89 g/ 12 g/mol

                  no. of mole =  1.3242

mole of C = 1.3242

For Oxygen

Molar mass of O = 16 g/mol

                  no. of mole = mass in g / molar mass

Put value in above formula

                  no. of mole =  21.18 g/ 16 g/mol

                  no. of mole =  

mole of O = 1.3238

For Os

Molar mass of Os = 190 g/mol

                  no. of mole = mass in g / molar mass

Put value in above formula

                  no. of mole =  62.93 g/ 190 g/mol

                  no. of mole =  

mole of Os = 1.3312

Now we have values in moles as below

C = 1.3242

O = 1.3238

Os = 1.3312

Divide the all values on the smalest values to get whole number ratio

C = 1.3242 /1.3238 = 1.0003

O = 1.3238 /1.3238 = 1

Os = 1.3312 /1.3238 = 1.0056

So all have round value 1 mole

C = 1

O = 1

Os = 1

So the empirical formula will be (OsCO) i.e. all 3 atoms in simplest small ratio

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asambeis [7]

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Explanation:

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Question 1<br>Amines have what type of functional group?<br>OH<br>O C=0<br>o H-C=0<br>-NH3<br>COOH​
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Answer:

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A. In a separatory funnel containing ethyl acetate and 10% aqueous sodium bicarbonate (NaHCO3), which layer would contain the br
castortr0y [4]

Answer:

ethyl acetate layer

Explanation:

This question tests your knowledge of the principle of solvent extraction.

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